Joshua walked 14 feet down the hall of his house to get the door he continued in a straight line out the door and across the yar
1 answer:
Answer:
Joshua walked 48 feet in total.
Step-by-step explanation:
To find the total distance we need to sum every distance that he walked. We have:
- First: Joshua walked down the hall to the door = 14 feet
- Second: He continued in a straight line out the door and across the yard to the mailbox = 24 feet
- Third: He came straight back across the yard and stopped to pet his dog = 10 feet
Hence, the total distance is:
Therefore, Joshua walked 48 feet in total.
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Answer:
- (a) see attached
- (b) width: 2x; height: y = 9-x²
- (c) A=2x(9-x²) . . . 0 ≤ x ≤ 3
- (d) dA/dx = -6x² +18; x=±√3
- (e) 12√3 units²
Step-by-step explanation:
(a) The attachment shows the graph of the parabola in blue. It also shows an inscribed rectangle in black.
(b) The upper right point of the rectangle is shown in the attachment as (x, y). The dimension y is the height of the rectangle. The x-dimension is half the width of the rectangle, which is symmetrical about the y-axis. Hence the width is 2x.
(c) As with any rectangle, the area is the product of length and width:
... A = (2x)(9 -x²) . . . . . the attachment shows a graph of this
... A = -2x³ +18x . . . . . expanded form suitable for differentiation
A suitable domain for A is where both x and A are non-negative: 0 ≤ x ≤ 3.
(d) The derivative of A with respect to x is ...
... A' = -6x² +18
This is defined everywhere, so the critical values will be where A' = 0.
... 0 = -6x² +18
... 3 = x² . . . . . . . divide by -6, add 3
... √3 = x . . . . . . . -√3 is also a solution, but is not in the domain of A
(e) The rectangle will have its largest area where x=√3. That area is ...
... A = 2x(9 -x²) = 2√3(9 -(√3)²) = 2√3(6)
... A = 12√3 . . . . square units . . . . ≈ 20.785 units²
Answer:
The scale factor is
Step-by-step explanation:
Yes the figures are similar to each other. The ratio of their linear measurements is in uniform ration
The ration of radius of large cylinder (R) to that of the smaller cylinder (r) is
Like wise the ration of height of large cylinder (H) to that of the smaller cylinder (h) is
The scale factor is