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LekaFEV [45]
3 years ago
10

Determine if the figures are similar. If they are, what is the scale factor from the first figure to the second figure?

Mathematics
1 answer:
lora16 [44]3 years ago
5 0

Answer:

The scale factor is \frac{3}{2}

Step-by-step explanation:

Yes the figures are similar to each other. The ratio of their linear measurements is in uniform ration

The ration of radius of large cylinder (R) to that of the smaller cylinder (r) is

\frac{18}{12} \\\frac{3}{2}

Like wise the ration of height of large cylinder (H) to that of the smaller cylinder (h) is

\frac{30}{20} \\\frac{3}{2}

The scale factor is \frac{3}{2}

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The 4th and 8th term of a G.P. are 24 and 8/27 respectively. find the 1st term and common ratio
beks73 [17]

Answer:

see explanation

Step-by-step explanation:

The n th term of a geometric progression is

• a_{n} = a₁ r^{n-1}

where a₁ is the first term and r the common ratio

given a₄ = 24, then

a₁r^{3} = 24 → (1)

Given a₈ = \frac{8}{27}, then

a₁r^{7} = \frac{8}{27} → (2)

Divide (2) by (1)

r^{4} = \frac{\frac{8}{27} }{24} = \frac{1}{81}

Hence r = \sqrt[4]{\frac{1}{81} } = \frac{1}{3}

Substitute this value into (1)

a₁ × (\frac{1}{3} )³ = 24

a₁ × \frac{1}{27} = 24, hence

a₁ = 24 × 27 = 648

4 0
4 years ago
what is the following product of assume Y is greater than or equal to 0 square root y to the third Times Square Root why 2/3​
sattari [20]

Step-by-step explanation:

\sqrt{y3}  \times   \sqrt{y3}

\sqrt{y3 \times y3}

\sqrt{y3 + 3}

\sqrt{y6}

4 0
3 years ago
Find the coefficient of the x7y2term in the binomial expansion of (x+y)^9
statuscvo [17]

Answer:

36

Step-by-step explanation:

first, see the formula in the attached picture.

now, by applying that formula we get :

the coefficient of the x7y2 is :

9C7 = 36  (you can either use a calculator or just the algebraic formula)

8 0
3 years ago
Which statement best describe the diagonals of a rhombus?
Drupady [299]
It’s d for sure I really believe it’s d
5 0
3 years ago
Read 2 more answers
‼️‼️‼️‼️HELP‼️‼️‼️‼️‼️‼️‼️
Vesnalui [34]

Michael took the return trip at a velocity 33.75 miles per hour.

<h3>How fast did Michael drive in his return trip?</h3>

Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.

First trip

45 = s / 3     (1)

Second trip

v = s / 4       (2)

By (1) and (2):

45 · 3 = 4 · v

v = 33.75 mi / h

Michael took the return trip at a velocity 33.75 miles per hour.

To learn more on velocities: brainly.com/question/18084516

#SPJ1

3 0
2 years ago
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