I need the answer written as a base and exponent not decimal. please and thanks

The following table gives the statements and justifications for solving the equation 4(x - 7) + 14 =

evablogger [386]

Answer:

From top to bottom:

Simplify

Combine like terms

Subtract 3x from both sides

Add 14 on both sides

Step-by-step explanation:

Hope this helps

4 0

2 years ago

Using the pattern, give the coefficients of (x + y)^5 and (x + y)^6

musickatia [10]

Answer:

$(x+y)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

$(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$

Step-by-step explanation:

In order to find the values of $(x+y)^5$ and $(x+y)^6$ , you need to apply the binomial theorem (high-level math you most likely don't need to worry about, it's easier than multiplying all the binomials together).

$(x+y)^5$ = $\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$ = $\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$ = $x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$ .

$(x+y)^6$ = $\sum _{i=0}^6\binom{6}{i}x^{\left(6-i\right)}y^i$ = $\frac{6!}{0!\left(6-0\right)!}x^6y^0+\frac{6!}{1!\left(6-1\right)!}x^5y^1+\frac{6!}{2!\left(6-2\right)!}x^4y^2+\frac{6!}{3!\left(6-3\right)!}x^3y^3+\frac{6!}{4!\left(6-4\right)!}x^2y^4+\frac{6!}{5!\left(6-5\right)!}x^1y^5+\frac{6!}{6!\left(6-6\right)!}x^0y^6$ = $x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$ .

5 0

3 years ago

Find the number that belongs in the green box.<br><br>Round your answer to the nearest tenth.

Natalija [7]

I think answer is the 10.

4 0

3 years ago

How do i tell whether the given side length is a right angle

erica [24]

Answer:

The sum of the lengths of any two sides of a triangle is greater than the length of the third side. If you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. If that is not true, then it is not possible to construct a triangle with the given side lengths.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Use the diagram on the right. How many planes contain both the line and the point

Aloiza [94]

Part (a)

<h3>Answer: 0</h3>

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Explanation:

Point P is part of 3 planes or faces of this triangular prism:

plane PEF (the front slanted plane)
plane PEH (the left triangular face)
plane PHG (the back rectangular wall)

Notice how each three letter sequence involves "P", though this isn't technically always necessary. I did so to emphasize how point P is involved with these planes.

Each of the three planes mentioned do not involve line FG

Plane PEF only deals with point F
Plane PEH doesn't have any of F or G involved
plane PHG only involves G

So there are no planes that contain line FG and point P.

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Part (b)

<h3>Answer: 0</h3>

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Explanation:

It's the same idea as part (a) earlier. The planes involving point G are

plane GQF (triangular face on the right)
plane GFE (bottom rectangular floor)
plane GHP (back rectangular wall)

None of these planes have line EP going through them.

As an alternative, we could reverse things and focus on all of the planes connected to line EP. Those 2 planes are

plane PEH (triangular face on the left)
plane PEF (front slanted rectangular face)

None of these planes have point G located in them.

8 0

3 years ago