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sladkih [1.3K]
3 years ago
11

A tennis ball on mars, where the acceleration due to gravity is 0.379g and air resistance is negligible, is hit directly upward

and returns to the same level 8.5 s later. (a) how high above its original point did the ball go? (b) how fast was it moving just after being hit? (c) sketch clear graphs of the ballâs vertical position, vertical velocity, and vertical acceleration as functions of time while itâs in the martian air
Physics
1 answer:
Studentka2010 [4]3 years ago
8 0

 To solve this, we use the formula:

y = v0 t + 0.5 a t^2

where y is distance, v0 is initial velocity, t is time and a is acceleration

 

Since we know that total time is 8.5 seconds, hence going up must be 4.25 s and going down is 4.25 s.

a = 0.379 g = 0.379 (9.8 m/s^2) = 3.7142 m/s^2

 

going up:

y = v0 (4.25) - 0.5 (3.7142) (4.25)^2

y = 4.25 v0 – 33.5439                       --> eqtn 1

 

going down:

y = 0 (4.25) + 0.5 (3.7142) (4.25)^2

y = 33.5439

y = 33.5439 m

 

Calculating for v0 from equation 1:

33.5439 = 4.25 v0 – 33.5439

4.25 v0 = 67.0877

v0 = 15.78535 m/s

 

answers:

a. y = 33.5439 m

b. v0 = 15.78535 m/s

c.

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The second dart leaves the gun two times as faster than the first one.

Explanation:

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7 0
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A block-and-tackle pulley hoist is suspended in a warehouse by ropes of lengths 2 m and 3 m. the hoist weighs 430 n. the ropes,
ICE Princess25 [194]
Refer to the diagram shown below.

For horizontal equilibrium,
T₃ cos38 = T₂ cos 50
0.788 T₃ = 0.6428 T₂
T₃ = 0.8157 T₂                (1)

For vertical equilibrium,
T₂ sin 50 + T₃ sin 38 = 430
0.766 T₂ + 0.6157 T₃ = 430
1.2441 T₂ + T₃ = 698.392        (2)

Substitute (1) into (2).
(1.2441 + 0.8157) T₂ = 698.392
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The magnetic field at the earth's surface can vary in response to solar activity. During one intense solar storm, the vertical c
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Answer:

EMF = 1684.67 Volts

Explanation:

As we know that EMF is induced in a closed conducting loop if the flux linked with the loop is changing with time

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now we have

A = (190 \times 10^3)(190 \times 10^3)

A = 3.61 \times 10^{10} m^2

now we have

EMF = 3.61\times 10^{10} (\frac{2.8 \times 10^{-6}T}{60 s})

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6 0
3 years ago
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Answer:

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Explanation:

4 0
3 years ago
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