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Relating the circumference to the force applied on the balloon, make a conclusion on the relationship of force to the rate of th

natka813 [3]

At a constant force, the mass of the balloon is inversely proportional to the rate of change motion of the balloon.

The force applied to an object can be determined by applying Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

where;

<em>m is the mass of the balloon</em>
<em>a is the change in velocity per time</em>

$F = m\frac{\Delta v}{t} \\\\\frac{F}{\frac{\Delta v}{t}} = m$

The mass of an object is inversely proportional to the rate of change motion of the object.

Thus, we can conclude that at constant force, the mass of the balloon is inversely proportional to the rate of change motion of the balloon.

Learn more here:brainly.com/question/15321240

3 0

3 years ago

Can anyone heelp me plzz plzz

Natali5045456 [20]

I think the answer is c) 1
Hope it helps and have a good day

4 0

3 years ago

An object of mass 30kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.

Luba_88 [7]

That all depends on the planet toward which the mass is falling.

If this happens to be taking place near the Earth, then the object accelerates
at the rate of about 9.8 meters per second every second.

Furthermore, if there is truly no air resistance, then it makes no difference whether
the object is a feather, a mass of 30 kg, or a school-bus. All objects accelerate at
the same rate regardless of their mass.

7 0

3 years ago

a ball is thrown upward with initial velocity of 20 m/s. (a) how long is the ball in the air? (b) what is the greatest height re

Lena [83]

a) t = 4.08 s

b) Response = 20.39m

c) t = 0.991 and 3.087 seconds.

Initially, the vertical speed was 20 m/s.

(a) how long is the ball in the air?

The ball is tossed upward, rises to its highest point, and then hits the ground again.

Consequently, the end height will be equal to the starting height.

h = h o = Om

Use the equation s= ut + -at.

2764 – An = 14

Put a negative sign for g because the ball is being thrown upwards and g is acting downwards.

Om = t - 0.5 * 9.81 m/s * 20 m/s

0 = 20 *t - 0.5 * 9.81 *t

20 *t=0.5*9.81 *t

20 = 0.5 * 9.81 *t

20 0.5*9.81

Answer (a): t = 4.08 s

(b) what is the greatest height reached by the ball?

Vertical velocity for the ball decreases to zero when it reaches its highest point.

Use the equation 2-u=295

-2ghmas for - u

(20m/s - (Om/s)2) = -2 * 9.81 m/s2 *

02 – 20= -2*9.81 *

-20% = -2 *9.81 *

202 = 2 * 9.81 *

b) RESPONSE: H = 20.39m

(c) when is the ball 15 m above the ground?

The ball will be 15 meters above the earth on two separate occasions.

1. When climbing

2. When descending

Use the equation s= ut + -at.

2,264 – fn = 4

0.5 * 9.81 m/s * 15m = 20 m/s*t

15 = 20 *t - 0.5 * 9.81 *t

15 = 20t – 4.9057

4.905 – 20t + 15 = 0

Calculator-based quadratic equation solution

(c) t = 0.991 and 3.087 seconds.

Hence the answers are,

a) t = 4.08 s

b) RESPONSE: Hmar = 20.39m

c) t = 0.991 and 3.087 seconds.

To learn more about initial velocity, click brainly.com/question/14154244

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4 0

1 year ago

How does an atom of bromine-79 become a bromide ion with a -1 charge?

Naily [24]

with a -1 iron charge it becomes an electrode

6 0

3 years ago

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