All categories

3 years ago

Which statement describes nuclear binding energy?

2 answers:

3 0

The answer for Plato users is C. It is the energy that is required to overcome mass defect.

From Plato "Nuclear binding energy is the energy that is required to overcome the energy that is used to keep the nucleus together, the mass defect."

Scorpion4ik [409]3 years ago

3 0

Answer: Option (B) is the correct answer.

Explanation:

As nucleus of an atom contains protons and neutrons and due to the same charge present n protons there will occur repulsion.

Hence, a binding energy will act on the nucleus of an atom which will bind the protons and neutrons together. When this binding energy is greater than the force of repulsion between the sub-atomic particles of a nucleus then the atom is stable.

Therefore, to change the nucleus of an atom high amount of energy is required. As a result, nuclear reactions tend to release large amount of energy due to changes in the nucleus of an atom.

Thus, we can conclude that the statement it is the energy that is required to bind protons and neutrons together in a nucleus, best describes nuclear binding energy.

You might be interested in

An airplane starts from rest and reaches a takeoff velocity of 60.0m/s due north in 4.0 s. How far has it traveled before takeof

Blizzard [7]

240 meters that's it

7 0

3 years ago

A 12 N force is used to pull a wagon 10 m to the left in 15 seconds. Which of the following represents the magnitude of the forc

Lana71 [14]

1. - 12N

2.- 2 hours

3. - 0.5 m/s/s

7 0

3 years ago

Read 2 more answers

In comparison to radio waves, visible light has:

Alexxx [7]

Answer:

Visible light has a shorter wavelength than radio waves

8 0

3 years ago

1. Do alto de uma plataforma com 15m de altura, é lançado horizontalmente um projéctil. Pretende-se atingir um alvo localizado n

sveta [45]

Answer:

(a). The initial velocity is 28.58m/s

(b). The speed when touching the ground is 33.3m/s.

Explanation:

The equations governing the position of the projectile are

$(1).\: x =v_0t$

$(2).\: y= 15m-\dfrac{1}{2}gt^2$

where $v_0$ is the initial velocity.

(a).

When the projectile hits the 50m mark, $y=0$ ; therefore,

$0=15-\dfrac{1}{2}gt^2$

solving for $t$ we get:

$t= 1.75s.$

Thus, the projectile must hit the 50m mark in 1.75s, and this condition demands from equation (1) that

$50m = v_0(1.75s)$

which gives

$\boxed{v_0 = 28.58m/s.}$

(b).

The horizontal velocity remains unchanged just before the projectile touches the ground because gravity acts only along the vertical direction; therefore,

$v_x = 28.58m/s.$

the vertical component of the velocity is

$v_y = gt \\v_y = (9.8m/s^2)(1.75s)\\\\{v_y = 17.15m/s.$

which gives a speed $v$ of

$v = \sqrt{v_x^2+v_y^2}$

$\boxed{v =33.3m/s.}$

4 0

3 years ago

You are at a friend’s house and they show you a magic trick. The balloon when brought near tiny pieces of paper is making the li

andrew11 [14]

Answer:

Static electricity.

Explanation:

Electric Charge; Is the quantity of electricity held in an object

The balloon is electrically neutral, meaning it had an equal amount of positive and negative charges hence it couldn't attract the paper.

After rubbing the balloon, it gained an electric charge; and after gaining this charge it got the ability to exert a force on the pieces of paper and attract them, This is called static electricity.

Therefore, Static electricity caused the paper to stick to the balloon.

5 0

3 years ago