A piece of metal has a density of 11.3 g/cm and a volume of
1 answer:
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Answer:
a) 4.94e9 J b) 1.07e10 J
Explanation:
The electric potential energy stored in a capacitor, expressed in terms of the value of the capacitance C, and the voltage between its terminals V, is as follows:
a) For the original capacitor, we can find directly U as follows:
U = 4.94*10⁹ J
b) Prior to find the electric potential energy of the upgraded capacitor, we need to find out the value of the capacitance C of this capacitor, which is identical to the original, except that has a different dielectric constant.
As the capacitance is proportional to the dielectric constant, we can write the following proportion:
ε₂ / ε₁ =
Once calculated the new value of the capacitance, as V remains the same, we can find the electric potential energy for the upgraded capacitor as follows:
⇒ U = 1.07*10¹⁰ J
Given:
m = 0.14 kg
v = 18 m/s
To find:
Kinetic energy= ?
Explanation:
Kinetic energy of the object is possessed when the object is in motion. It is define as the work done required to accelerate a body from rest to motion. Unit of energy is Joule and it is same as unit of work done. Energy is nothing but the capacity to do work.
Solution:
Kinetic energy of the ball is given by,
Kinetic energy =
m = 0.14 kg
v = 18 m/s
Kinetic energy =
Kinetic energy = 226.8 Joule