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4 years ago

Why type of association does the graph show between x and y?

Mathematics

2 answers:

faust18 [17]4 years ago

8 0

Where is the graph at?

Dmitrij [34]4 years ago

4 0

Theres no graph tho where is it

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Select all of the relations that are functions. {(a, 1), (b, 1), (c, 1)} {(a, a), (a, b), (a, c)} {(1, a), (2, a), (3, a)} {(a,

netineya [11]

Answer:

{(a, 1), (b, 1), (c, 1)}, {(1, a), (2, a), (3, a)}, and {(a, a), (b, b), (c, c)}

**All functions are relations, but not ll relations are functions**

In a function, the x values CAN NOT repeat, only y-values can.

5 0

3 years ago

A. convert to the indicated unit of measure<br><br> 1.708mm=_m

valina [46]

Answer:

the answer is

0.001708 meter

8 0

3 years ago

Read 2 more answers

I need help please 20 mins

Naily [24]

They are alternate exterior angles... Which means they are the same so x=132.

Hope it helps! Comment if you have any questions and have an amazing day!

3 0

3 years ago

Read 2 more answers

suppose we want to choose 6 letters without replacement from 13 distinct letters. A) how many ways can this be done if order doe

kiruha [24]

Answer: A) 1716 B) 1235520

Step-by-step explanation:

If order doesn't matter , then we use combinations, where the number of combinations of selecting r things from n is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

If order matters , then we use permutations, where the number of permutations of selecting r things from n is given by :-

$^nP_r=\dfrac{n!}{(n-r)!}$

Given, Total distinct letters = 13

To choose = 6 letters

A) Number of ways to choose (if order does not matter)= $^{13}C_6$

$=\dfrac{13!}{6!7!}=\dfrac{13\times12\times11\times10\times9\times8\times7!}{(720)\times 7!}\\\\= $$1716$

B) Number of ways to choose (if order matters)= $^{13}P_6$

$=\dfrac{13!}{7!}=\dfrac{13\times12\times11\times10\times9\times8\times7!} 7!}\\\\= $$1235520$

Hence, A) 1716 B) 1235520

5 0

4 years ago

Suppose that the functions f and g are defined for all real numbers x as follows.

vovangra [49]

Answer:

(f+g)(x)=5x-4

(f*g)(x)=(4x^2-19x-5)

(f-g)(3)=(-15)

Step-by-step explanation:

(f+g)(x)=(x-5)+(4x+1)=(5x-4)

(f*g)(x)=(x-5)(4x-1)=(4x^2-19x-5)

(f-g)(3)=(x-5)-(4x-1)=(3-5)-(4(3)+1)=(-2)-(12+1)=(-2)-(13)=-15 substitute 3 for x

6 0

3 years ago