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noname [10]
3 years ago
6

Which of the following prefixes would be best for measuring small objects like the width of a piece of paper?

Mathematics
2 answers:
Valentin [98]3 years ago
7 0
Hecta is the prefix meaning 100 times;
Kilo means 1000 times;
Deca is one tenth;
and Centi is one hundredth.
In this case, the smallest and most suitable for measuring small objects would be Centi.
avanturin [10]3 years ago
6 0

From Largest to smallest unit of measure:

KILO means 1000

HECTO means 100

DEKA means 10

DECI means 1/10

CENTI means 1/100

MILLI means 1/1000

Accordingly, the answer is 4 or D, for Centi. Of the options provided Centi is the smallest unit of measure. Width is a red herring to confuse you.

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The dimensions that minimizes the cost are a= 6.604 (lenght of a side) and h=2.752 (height)

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Let's define some notation first:

h = represent the height of the box

a= length of a side on the bottom

We need to remember that we have on this case an open box, so then we don't have a top part.

Let's begin with the formula for the volume of the box, we have a total volume given of 120m^3, and we know that the volume for a box is the product of the area and the height like this:

120 m^3 = a^2 h   (1)

From equation (1) we cna solve for the height and we got:

h=\frac{120}{a^2}   (2)

Now let's move to th surface area formula. The top bottom area is a^2 and the surface area for the four lateral sides is 4ah. Since we know that the cost for the bottom material is 10 $ per each square meter and for the sides is 12$ per square meter we can create a function cost like this:

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Now we can substitute into equation (3) the equation (2) like this:

Cost = 10a^2 + (12)(4ah) = 10a^2 + 48a\frac{120}{a^2}=10a^2 +\frac{5760}{a}   (4)

Now in order to find the minimum cost, we can take the first derivate for the expression (4) like this

\frac{d}{da} Cost = 20a -\frac{5760}{a^2}

We can set this equal to 0 and solve for a and we got:

\frac{5760}{a^2}= 20a

\frac{5760}{20}=a^3

a=6.604

And since we have a we can find h using the expression (2) like this:

h=\frac{120}{a^2}=\frac{120}{6.604^2}=2.752  

So then the dimensions that minimizes the cost are a= 6.604 (lenght of a side) and h=2.752 (height)

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