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Dominik [7]
3 years ago
6

Someone plz be helpful and help a brother out

Mathematics
1 answer:
boyakko [2]3 years ago
8 0

Answer:

x = 11°

I don't know about the second

it's a correct answer.

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Find the real solution(s) of the following equation.
nydimaria [60]

Answer:

a=9

Step-by-step explanation:

a^3 = 729

Taking the cube root of each side

a^3 ^(1/3) = 729^ (1/3)

a = 9

4 0
2 years ago
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What two rational expressions sum to <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4x%2B2%7D%7Bx%5E%7B2%7D-9%2B8%20%7D" id="TexFor
bulgar [2K]

Answer:

\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}

Step-by-step explanation:

Given

\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}

Required

Fill in the gaps

Going by the given parameters, we have that

\frac{4x+2}{x^{2}-9+8 } = \frac{A}{()(x-1)} + \frac{B}{()(x-8)}

x^2 - 9x + 8, when factorized is (x-1)(x-8)

Hence; the expression becomes

\frac{4x+2}{(x-1)(x-8)} = \frac{A}{(x-8)(x-1)} + \frac{B}{(x-1)(x-8)}

Combine Fractions

\frac{4x+2}{(x-1)(x-8)} = \frac{A + B}{(x-8)(x-1)}

Simplify the denominators

4x + 2 = A + B

By direct comparison

A = 4x

B = 2

Hence, the complete expression is

\frac{4x+2}{x^2 - 9x + 8} = \frac{4x}{(x-8)(x-1)} + \frac{2}{(x-8)(x-1)}

3 0
3 years ago
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At the market, 7 apples cost $4.55. How much do 9 apples cost?
Dvinal [7]
7 apples = 4.55
To find the single cost of an apple, divide 4.55 by 7
4.55/7 = 0.65 per apple
Let's check to see if this is right.
0.65 x 7 = 4.55 = correct
0.65 x 9 = $5.85 for 9 apples

6 0
3 years ago
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Pls help how do i solve for x in this equation??
evablogger [386]

Answer:

x = -2

Step-by-step explanation:

1. Square both sides
x^2 +3x + 6 = x^2
2. Subtract x^2 from both sides
3x + 6 = 0
3. Subtract 6 from both sides and divide by 3
x = -2

6 0
1 year ago
Find the value of x to the nearest tenth.<br><br> 10.0<br> 6.0<br> 9.3<br> 4.0
SVETLANKA909090 [29]
Suppose that the value of other ratio is equal to 6/3 then,

20/3x-8 = 6/3
18x-48 = 60
18x = 60+48
18x = 108
x = 6
7 0
3 years ago
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