Answer:
C. H 0 : μ = 7 vs. Ha : μ ≠ 7
Since the calculated value of t = -9.462 falls in the critical region t ≤-2.048
We conclude that the springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.
Step-by-step explanation:
The null hypothesis the usually the test to be performed. Here we want to check whether the water is neutral or not. Neutral water must have a pH of 7 . This can be stated as the null hypothesis. And the claim is treated as the alternate hypothesis that water in not neutral or not having pH= 7
In symbols it will be written as
H0: : μ = 7 vs. Ha : μ ≠ 7
So choice C is the best option for this hypothesis testing.
Let the significance level be 0.05
The degrees of freedom = n-1= 29-1 = 28
The critical value is t ≥ 2.048 and t ≤ - 2.048 for 0.05 two tailed test with 28 df.
The test statistic to use is t- test
t= x- u/ s/√n
The total sum is 170.9 and mean = x= 5.893
The u = 7
And the sample standard deviation is =s= 0.63
Putting the values
t= 5.893-7/0.63/√29
t= - 1.107/0.11699
t= -9.4623
Since the calculated value of t = -9.462 falls in the critical region t ≤-2.048
We conclude that the springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.
Angle w equals 130 degrees.
Explanation:
A line equals: 180 degrees total.
180-50=130
Answer:
3y + 2 =
Step-by-step explanation:
7y - 4y = 3y
3y and 2 are not like terms, so you can't add any further
The amount to be invested today so as to have $12,500 in 12 years is $6,480.37.
The amount that would be in my account in 13 years is $44,707.37.
The amount I need to deposit now is $546.64.
<h3>How much should be invested today?</h3>
The amount to be invested today = future value / (1 + r)^nm
Where:
- r = interest rate = 5.5 / 365 = 0.015%
- m = number of compounding = 365
- n = number of years = 12
12500 / (1.00015)^(12 x 365) = $6,480.37
<h3>What is the future value of the account at the end of 13 years?</h3>
Future value = monthly deposits x annuity factor
Annuity factor = {[(1+r)^n] - 1} / r
Where:
- r = interest rate = 5.3 / 12 = 0.44%
- n = 13 x 12 = 156
200 x [{(1.0044^156) - 1} / 0.0044] = $44,707.37
<h3>What should be the monthly deposit?</h3>
Monthly deposit = future value / annuity factor
Annuity factor = {[(1+r)^n] - 1} / r
Where:
- r = 6.7 / 12 = 0.56%
- n = 2 x 12 = 24
$14,000 / [{(1.0056^24) - 1} / 0.0056] = $546.64
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