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Finger [1]
3 years ago
7

Sorry again what is 9,576,297 in word form

Mathematics
1 answer:
belka [17]3 years ago
6 0

Answer:

Nine-million,five hundred seventy-six thousand, two hundred ninety-seven

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Chris plans to buy a car that depreciates in value at a rate of 10% per year. If the car initially costs $32,000. How much will
VLD [36.1K]
The car would be worth $16,000 after 5 years.
5 0
3 years ago
NO SCAM. PLEASE SHOW WORK. WILL GIVE BRAINLY TO CORRECT ANSWER.
sergeinik [125]

Answer:

140

Step-by-step explanation:

A regular polygon is a shape with equal sides and angles. Because of this, we can write the following equation to set two sides equal to each other:

3a+b+3=2a+2b+6

Solving, we will get a in terms of b:

3a=2a+b+3,\\a=b+3

Now we can substitute a for (b+3) into our equation:

5a-2b+1=2a+2b+6,\\5(b+3)-2b+1=2(b+3)+2b+6,\\3b+16=4b+12,\\-b=-4,\\b=\boxed{4}

Therefore, the length of each side of this polygon is 5(4+3)-2(4)+1=28.

Since the perimeter of the polygon consists of all five sides, the perimeter is:

p=28\cdot 5 =\boxed{140}

6 0
3 years ago
Read 2 more answers
The store paid $2.70 for a book and sold it for $6.20. What is the profit as a percent?
Alenkinab [10]

Answer:

129.6% profit

Step-by-step explanation:

1)Firstly in order to find the overall profit you take away $2.70 from $6.20 = $3.50

2)The next step is to put the profit over the amount paid = 3.50/2.70 = 35/27.

3)In order to find the percentaage you multiply 35/27 by 100 = 129.629 recurring. This rounded to 1 decimal place is 129.6%

Thank you for reading, please let me know if I've missed anything out!

5 0
2 years ago
This question below.
pochemuha
I can’t really see what it says but it it’s total surface area it’s 9044.3 but it it’s lateral surface are it’s 7840
6 0
3 years ago
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

t=-\text{ln}(\frac{1}{3})\cdot 20

t=-(\text{ln}(1)-\text{ln}(3))\cdot 20

t=-(0-\text{ln}(3))\cdot 20

t=20\text{ln}(3)

Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

6 0
3 years ago
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