They y-axis represents the -3 now all that you need to do is line it up to -3 and 3 in the graph
The simplest solution is:
2452 = 60q +52r
2452 = 60q + 52(1)
2452 -52 = 60q
2400 = 60q
2400/60 =q
40 = q
r = 1: q = 40
Answer:
Area ABCDE = 82 cm²
Step-by-step explanation:
ABCDE = ΔEAD + ΔDAC + ΔCAB
ABCDE = (12×5)/2 + (12×6)/2 + (8×4)/2 = 30+36+16 = 82
Answer:The measure of the arc RPQ is 205°
Step-by-step explanation:
Given the figure in which
m∠ROP=125°
we have to find the measure of the arc RPQ.
As QP is diameter i.e a straight line therefore
∠1 and ∠2 forms a linear pair hence these angles are supplementary.
By supplementary law
∠1+∠2=180°
∠1+125°=180°
∠1=180°-125°=55°
Now we have to find the measure of the arc RPQ i.e
we have to find the measure of ∠2+∠3
By theorem, angles around a point will always add up to 360 degrees.
∴ ∠1+∠2+∠3=360°
55°+∠2+∠3=360°
∠2+∠3=860-55=205°
Hence, the measure of the arc RPQ is 205°
