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zhuklara [117]
3 years ago
11

Evaluate cot(-405°) I need help please

Mathematics
2 answers:
GarryVolchara [31]3 years ago
7 0

Answer:

-1

Step-by-step explanation:

It always happens that:

\cos \theta = \frac{1}{\tan \theta}

So, we will find \tan (-405). In order to do that, remember that \tan \theta = \tan \theta + 180. Then

\tan(-405) = \tan(-405 + 180) =\tan(-225)

We repeat that until we have a positive number in the argument.

\tan(-225) = \tan(-225 + 180) =\tan(-45)

\tan(-45) = \tan(-45 + 180) =\tan(135)

As we can see, we have to find \tan(135). If we draw an angle of 135, we can see in the image that the abscissa is negative (because is in the left), and the ordinate is positive. Then

\tan(135) = -\tan(45) = -1.

Finally

\tan(-405) = -1.

(tan(45) is a known value. Also the tan(30) and tan(60). You can usually go from there)

LuckyWell [14K]3 years ago
5 0
x^\circ = x^\circ +360n
where n is a whole number

cot (\theta) = \frac{1}{tan(\theta)}
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3 years ago
Help<br><br> Determine which equation is parallel to line jk and which is perpendicular to line jk.
alukav5142 [94]

Answer:

5x + 3y = 13 parallel.

6x - 10y = 7 perpendicular.

Step-by-step explanation:

Two lines with slopes m_1 and m_2 are parallel when m_1=m_2 and are perpendicular when m_1*m_2=-1

Now determine the slope of all the lines

The line jk passes through the points

(-5,5) and (1,-5) so its slope is

\frac{-5-5}{1-(-5)}=\frac{-10}{6}=-\frac{5}{3}

To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope

5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3

Neither parallel nor perpendicular.

6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5

Neither parallel nor perpendicular.

5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3

This line is parallel

6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5

Since (-5/3)(3/5) = -1 this line is perpendicular.

8 0
3 years ago
First and second place in the contest use a ratio to share a cash prize when first place pays $100 second please pay $60 how muc
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100/60 = x/36

Cross Multiply

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First place pays $60 when second place pays $36.

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4 0
3 years ago
Keirra’s mother gave her $7.50 to buy 8 spiral notebooks. With tax, the cost of each notebook is $1.05. Does Keirra have enough
GuDViN [60]

Answer:

No

Step-by-step explanation:

each notebook is $1.05 and the is $7.50

there is only enough for seven notebooks not eight.

7 0
3 years ago
The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation c = 3. 5b. Whi
Allisa [31]

You can use the fact that number of breads purchased cannot be negative since a customer either buys them or not and usually do not sell to the shopkeeper.(if somehow they end up selling to shop owner, then yes that will go in negative, but we'll assume it is wrong in most cases as generally shop owners are there to sell stuffs).

The third table of values matches the equation and includes only viable solutions.

<h3>What is a viable solution here?</h3>

It is talking about those solutions which are seen in real world. As stated above, a customer either buys the bread or not, thus number of breads sold will be either positive or 0(in case of no selling). Thus, we cannot have number of breads as negative.

Such solutions which are correct in the real world context here are called here as viable solutions.

<h3>Checking one by one all the tables for them being matched with table and viability</h3>

For first table, the number of breads are in negative, thus it is not going to have viable solution.

For second table, we have:

b = 0 thus c = 3.5b = 3.5 times 0 = 0 which is correctly given in second column.

b = 0.5, thus c = 3.5b = 3.5 times 0.5 =1.75 which is correctly given.

b = 1, thus c= 3.5 times 1 = 3.5 which is correctly given

b = 2001.5 thus c = 3.5 times 2001.5  = 7005.25 which is not correctly given, thus wrong.

For third table, we have:

b = 0, thus c = 3.5 \times 0 = 0, correctly given in second column.

b = 3, thus c = 3.5 \times 3 = 10.5, correctly given.

b = 6, thus c = 3.5 \times 6 = 21, correctly given.

b = 9, thus c = 3.5 \times 9 = 31.5, correctly given.

Thus, the third table of values matches the equation and includes only viable solutions.

Learn more about purchasing to cost relation here:
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