All categories

3 years ago

Solve the following quadratic equation for all values of x in simplest form. 20+ 2x= 28

Mathematics

1 answer:

n200080 [17]3 years ago

6 0

Answer:

x = 4

Step-by-step explanation:

To solve, we need to isolate x.

Start by moving the 20 to the other side by subtracting it from both sides.

2x = 8

Since x is being multiplied by 2, we need to divide both sides by 2 to move it to the other side.

x = 4

You might be interested in

6xTo the -1st power times Y to the fifth power times 4X to the -4th power times Y to the -2nd power

Andrew [12]

i don't know how to type the answer out but it's on the work i just did ⬆️

7 0

3 years ago

How old am i if 200 reduced by 2 times my age is 16

Rashid [163]

$x-\ you're\ age\\\\
200-2x=16\ \ \ | subtract\ 200\\\\
-2x=-184\ \ \ | divide\ by\ -2\\\\
x=92\\\\
You\ are\ 92\ years\ old.$

3 0

3 years ago

Sam has ⅙ of a book left to read. He wants to finish the book by reading the same amount every day for 4 days. How much of the b

babymother [125]

4 (1/16) = 4/16 = 1/4

(1/4) / 4 = 1/16 each day

7 0

3 years ago

Read 2 more answers

Assume the readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees

lozanna [386]

Answer: 0.0035

Step-by-step explanation:

Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

i.e. $\mu=0$ and $\sigma= 1$

Let x denotes the readings on thermometers.

Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_

$P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035$

Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035

The required region is attached below .

8 0

3 years ago

Denise Cho is a broadcast technician and earns $29.00 an hour with time and a

Vladimir79 [104]

hsksebhssv hnshsnsjdndj ldgehsiw c 3072729 lvwjaiwn sj. +a iwiwirbfhx ska hamd +675196 = $ 20000 solved

4 0

1 year ago