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sweet-ann [11.9K]
3 years ago
9

Verify (2cos2x)/(sin2x) =cotx - tanx

Mathematics
1 answer:
lianna [129]3 years ago
6 0
Cos2x = (cosx)^2 - (sinx)^2;
sin2x = 2sinxcosx;
Then, (2cos2x)/(sin2x) =2[ (cosx)^2 - (sinx)^2 ] / (2sinxcosx) = [ (cosx)^2 - (sinx)^2 ] / (sinxcosx) = (cosx)^2 / (sinxcosx) - (sinx)^2 / (sinxcosx) = cosx/sinx - sinx/cosx = cotx - tanx;
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