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xxTIMURxx [149]
3 years ago
7

A policeman is standing near a highway using a radar gun to catch speeders. He aims the gun at a car that has just passed his po

sition and, when the gun is pointing at an angle of 45(degrees) to the direction of the highway, notes that the distance between the car and the gun is increasing at a rate of 100km/h. How fast is the car travelling?
...?
Mathematics
1 answer:
Serhud [2]3 years ago
4 0
The speed obtained is the y-component of the actual speed of the car. The y-component and actual speed are related by:
Vy = Vsin(∅)
100 = Vsin(45)
V = 141.4 km/h
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Z = -400i - 44.5<br> What is the imaginary part of z?
hjlf

Answer:

-400i

General Formulas and Concepts:

<u>Algebra II</u>

  • Complex Form: a + bi

Step-by-step explanation:

<u>Step 1: Define</u>

z = -400i - 44.5

<u>Step 2: Identify</u>

Treat imaginary <em>i</em> as a variable. The imaginary part of z would be the entire term of <em>i</em>. Therefore, our answer is -400i

6 0
2 years ago
Subtract the quotient of 15 ÷ 3 from the sum of 33 and 7.
Tems11 [23]
15:3=5\\33+7=40\\\\33+7-15:3=40-5=\fbox{35}\leftarrow answer\ \boxed{C}
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3 years ago
Read 2 more answers
The range of all real numbers x such that 2x − 5 &lt; 7 and 4x + 10 &gt; 6 is . The range of all real numbers x such that 2x − 5
lisov135 [29]

Solution for Part 1:

2x − 5 < 7 and 4x + 10 > 6 is called a compound inequality. To find the range we need to solve each of the inequality and range would be the values of x which will make both the inequality TRUE.

Solving inequality 2x - 5 < 7:

2x - 5 < 7 {adding 5 on both sides}

2x - 5 + 5 < 7 + 5 {Combining like terms in either side of inequality}

2x < 12 {Dividing 2 on both sides}

2x/2 < 12/2 {Simplifying fraction in either side of inequality}

x < 6

Solving inequality 4x + 10 > 6:

4x + 10 > 6 {Subtracting 10 on both sides of inequality}

4x + 10 - 10 > 6 -10 {Combining like terms on either side}

4x > -4 {Dividing by 4 on both sides}

4x/4 > -4/4 {Simplifying each fraction}

x > - 1

Range of 2x − 5 < 7 and 4x + 10 > 6 will be all the x value which satisfy both the inequality x < 6 and x > -1.

Conclusion Part 1:

The range of all real numbers x such that 2x − 5 < 7 and 4x + 10 > 6 is can be given by interval notation (-1, 6)

Solution for part 2:

2x − 5 < 7 or 4x + 10 > 6 is called a compound inequality. To find the range we need to solve each of the inequality and range would be the values of x which The solution is same as part 1, with a small difference.

Range of 2x − 5 < 7 or 4x + 10 > 6 will be all the x value which satisfy any one of the inequality x < 6 or x > -1.

Conclusion Part 2:

The range of all real numbers x such that 2x − 5 < 7 or 4x + 10 > 6 is can be given by interval notation (-∞, ∞)

Note:

(i) When two inequalities are joined by the word and, the solution of the compound inequality occurs when both inequalities are true at the same time. It is the overlap, or intersection, of the solutions for each inequality.

(ii) When the two inequalities are joined by the word or, the solution of the compound inequality occurs when either of the inequalities is true. The solution is the combination, or union, of the two individual solutions.

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3 years ago
1,679 rounded to the nearest thousand
polet [3.4K]
The answer is 1700 because 1679 rounded to the nearest hundred is 1700
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2 years ago
Find the slope of the line.<br><br> A: 1/2<br> B: - 1/2<br> C: -2<br> D: 2<br><br> Please Help
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It is B) -1/2 you btw you don't have to put please help :)
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3 years ago
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