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xxTIMURxx [149]
3 years ago
7

A policeman is standing near a highway using a radar gun to catch speeders. He aims the gun at a car that has just passed his po

sition and, when the gun is pointing at an angle of 45(degrees) to the direction of the highway, notes that the distance between the car and the gun is increasing at a rate of 100km/h. How fast is the car travelling?
...?
Mathematics
1 answer:
Serhud [2]3 years ago
4 0
The speed obtained is the y-component of the actual speed of the car. The y-component and actual speed are related by:
Vy = Vsin(∅)
100 = Vsin(45)
V = 141.4 km/h
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Answer:

2s+\left(-4s\right)=-2s is the equivalent expression as 2s+\left(-4s\right) is equal to -2s.

Step-by-step explanation:

Considering the expression

2s+\left(-4s\right)

As we know that

  • Like terms are said to be the terms which hold the same variables raised to the same power.
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Lets solve the expression

2s+\left(-4s\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

2s-4s

\mathrm{Add\:similar\:terms:}\:2s-4s=-2s

-2s

Therefore,

2s+\left(-4s\right)=-2s is the equivalent expression as 2s+\left(-4s\right) is equal to -2s.

Keywords: equivalent expression, like terms

Learn more about equivalent expression from brainly.com/question/8902137

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dsp73

Answer:

a) \log 52

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Step-by-step explanation:

Use logarithm properties:

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