In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.
<h3>What is the variables about?</h3>
Note that:
y=-8x+4
y-4=-8x
(y-4)/-8=x
Since the independent variable x is known, one can switch the variable labels and thus it will be:
y=(x-4)/-8
f^-1(x)=(x-4)/-8
This can be written again as:
f^-1(x)=(4-x)/8 :P
Thus one can say No, as he forgot to switch the variable labels after solving for the independent variable.
In the case above, Talib work is not correct as one need to first switch x and y before one can solve for y.
See the first part of the question below
Talib is trying to find the inverse of the function to the right. His work appears beneath it. Is his work correct? Explain your answer.
Learn more about variable from
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Answer:
The Y intercept adds on +6 every time.
Step-by-step explanation:
Hope this helps! :3
2 Answers: Choice B and Choice C
The rate of change is 2.
The rate of change is constant.
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Explanation:
The first point on the left is when x = 1.5 and it has a height of y = 1
The point (1.5, 1) is on the line.
So is the point (3,4) for similar reasoning.
Compute the slope between those points
m = (y2-y1)/(x2-x1)
m = (4-1)/(3-1.5)
m = 3/(1.5)
m = 2
The slope is 2, which is the same as saying the rate of change is 2. This only applies when x > 1 of which the interval 1.5 ≤ x ≤ 3 is a part of.
Since the slope stays at 2 on the interval 1.5 ≤ x ≤ 3, this means we consider the slope to be constant. If the curve bended at all on this interval, then it wouldn't be a constant slope.
Answer:
n 3 is the correct answer okay
9514 1404 393
Answer:
- left 1 unit
- down 2 units
Step-by-step explanation:
The transformation g(x) = f(x -h) +k is a translation of f(x) to the right by h units and up k units.
1. h = -1, so the graph of g(x) is the graph of f(x) shifted left 1 unit. (blue)
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2. k = -2, so the graph of g(x) is the graph of f(x) shifted down 2 units. (green)