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Sav [38]
3 years ago
15

When to use Sine and Cosine and Tan Laws

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
5 0
'you use sine = opposite/ hypotenuse

you use cosine = adjacent/ hypotenuse

you use tan laws= opposite/adjacent
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What is the value of each one​
Zinaida [17]

Answer:

t5ju8i8

Step-by-step explanation:

7 0
2 years ago
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3) Lane and Zack purchased a house for $245,000 in 2016. The house loses 4% of its value each year,
alina1380 [7]

Answer:

$138,345

Step-by-step explanation:

This is a compound decline problem, which will be solve by the compound formula:

F=P(1-r)^t

Where

F is the future value (value of house at 2030, 14 years from  2016)

P is the present value ($245,000)

r is the rate of decline, in decimal (r = 4% = 4/100 = 0.04)

t is the time in years (2016 to 2030 is 14 years, so t = 14)

We substitute the known values and find F:

F=P(1-r)^t\\F=245,000(1-0.04)^{14}\\F=245,000(0.96)^{14}F=138,344.96

Rounding it up, it will be worth around $138,345 at 2030

8 0
3 years ago
What is the interquartile range(IQR) of the data set represented by this box plot?
Nesterboy [21]
IQR=Q3-Q1
73-51=22
Answer:22
5 0
3 years ago
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Can someone help me in number 3 please
Sholpan [36]

Area of rectangle is the multiplication between the sides.


The first rectangle:


A = (2x + 5) . (3x - 2)

A = 2x . 3x - 2 . 2x + 5 . 3x - 2 . 5

A = 6x² - 4x + 15x - 10

A = 6x² + 11x - 10


The second rectangle:


A = (5y + 5) . (2y - 3)

A = 5y . 2y - 3 . 5y + 5 . 2y - 3 . 5

A = 10y² - 15y + 10y - 15

A = 10y² - 5y - 15

4 0
3 years ago
Heather drove 265 miles using 10 gallons of gas. At this rate, how many gallons of gas would she need to drive 424 miles?
slava [35]

Answer:

Step-by-step explanation:

Next bit of info that we have is 424 miles. Miles go on the numerator, and gallons, which we will call "x" will go on the denominator. It should be set up like this: 265/10 = 424/x Once you cross multiply you should get 265x=4240. Divide 265 by both sides and the answer is 16 gallons.  Sorry if its wrong

6 0
2 years ago
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