Answer:
$8950.37
Step-by-step explanation:
Use the compound amount formula A = P(1 + r/n)^(nt), in which P is the initial amount of money (the principal), r is the interest rate as a decimal fraction, n is the number of times per year that interest is compounded, and t is the number of years.
Here we have A = $11,000, n = 2, r = 0.07 and t = 3, and so:
$11,000 = P(1 + 0.07/2)^(2*3), or
$11,000 = P (1.035)^6
$11,000 $11,000
Solving for P, we get P = ---------------- = ------------- = $8950.37
1.035^6 1.229
Depositing $8950.37 with terms as follows will result in an accumulation of $11,000 after 3 years.
Answer:
did she like it?
Step-by-step explanation:
Answer:
The answers are: a, c, d, e
Step-by-step explanation:
I hope this helps
Answer:
D
Step-by-step explanation:
Plug in and see.
Check A: Lets plug in (0,3) into y<2/3 x+2.
3<2/3 (0)+2
3<2 is not true so not A
Check C: Lets plug in (3,5) into y<2/3 x+2.
5<2/3 (3)+2
5<2+2
5<4 is not true so not C
Check B: Lets plug in (-3,1) into y<2/3 x+2.
1<2/3 (-3)+2
1<0 is not true so not B
Check D: Lets plug in (1,2) into y<2/3 x+2.
2<2/3 (1)+2
2<2/3+2 is true so D
