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Marina86 [1]
3 years ago
6

What is the product of 14,560 times 10 and explain the number of zeros

Mathematics
2 answers:
VashaNatasha [74]3 years ago
6 0

14,560
× 10
-----------
00,000
+145,600
--------------
145,600 ↔answer
Alexandra [31]3 years ago
6 0
14,560 times 10 would be 145,600. All you have to do is add how ever many zeros there are in the number to the sum. Whether it be 14,560 times 200 or 10 you multiply it by the first number then take the sum of it and add the zeros.
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Solve the given triangles by finding the missing angle and other side lengths.
coldgirl [10]

Answer:

  1. a ≈ 27.65; B = 28°; c ≈ 19.17
  2. a ≈ 163.30; B = 120°; c ≈ 59.77
  3. A = 13°; b ≈ 0.3874; c ≈ 1.3737

Step-by-step explanation:

As long as you're seeking outside help, the use of a suitable tool is appropriate. Many graphing calculators, apps, and web sites are available for solving triangles.

__

Here, you're given two angles and a side. The third angle is the difference from 180° of the sum of the other two. For example, in the first problem, ...

  B = 180° -A -C = 28°

The missing sides are found using the law of sines. Since you are given a side, use that as the reference, and its opposite angle as the reference angle. Then you have ...

  side = sin(opposite angle)×<em>((reference side)/sin(reference angle))</em>

Note that the factor in italics remains the same for both remaining sides.

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In the first problem, this becomes ...

  a = sin(112°)·14/sin(28°) ≈ 27.65

  c = sin(40°)·14/sin(28°) ≈ 19.17

__

The remaining problems are worked in similar fashion.

_____

<em>Comment on triangle solutions</em>

These are straightforward because you're given two angles. If you're given two sides and an angle, the solution method varies depending on which angle you're given (opposite the long side, the short side, or the unknown side). In the last case, the law of cosines is involved. In the second case, there are likely two solutions. Once you have two angles, you can proceed as above.

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Explain why you cannot factor the trinomial x(to the power of 2)−12x+6
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Answer:

See below

Step-by-step explanation:

You cannot find two whole number integers that give a sum of -12 and a product of 6.

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