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mars1129 [50]
2 years ago
7

5. The box plot summarizes the test scores for 100 students: u 55 60 65 70 75 80 85 90 95 100 Which term best describes the shap

e of the distribution? a. bell-shaped C. skewed b. uniform d. symmetric​

Mathematics
1 answer:
ASHA 777 [7]2 years ago
7 0
C would be the correct answer
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What is the y-value when x equals 7?<br> y = 310 - 25(x)
monitta

Answer:

y=135

Step-by-step explanation:

To find the solution, we must put 7 in for x and solve, as shown:

y=310-(25)(7)\\y=310-175\\y=135

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3 years ago
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Help fast plz I WILL DO ANYTHING
kaheart [24]

Answer:

I only have 2

Step-by-step explanation:

each sides is multiplying by 2

each order is multiplying by 12

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3 years ago
HELP it's a maths question worth 4 marks
Ksenya-84 [330]

a = 3, b= - 4 and c = - 4

expand the left side using FOIL

(2x + 1)(ax + b) = 2ax² + 2bx + ax + b = 2ax² + x(2b + a) + b

compare the coefficients of expressions on left and right sides.

compare 2ax² + x(2b +a) + b with 6x² - 5x + c

coefficients of x² terms → 2a = 6 ⇒ a = 3

coefficients of x terms → 2b + a = - 5 → 2b + 3 = - 5 → 2b = - 8 ⇒ b = - 4

constant terms c = b = - 4


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3 years ago
The sum of the roots of the quadratic 5x^2 - 6x + 1 = 0 is
MatroZZZ [7]

Answer:

here's your answer

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3 years ago
The roosevelt middle school band is having a fundraiser. They sold a total of 300 hotdogs and hamburgers. Hot dogs were sold for
STALIN [3.7K]

Answer:

180 hamburgers

120 hotdogs

Step-by-step explanation:

In this question, we are asked to calculate the number of hamburgers and hotdogs sold by a company given the amount made by them and the total number of these snacks sold

We proceed as follows;

Let the amount of hotdogs sold be x and the amount of hamburgers sold be y.

We have a total of 300 snacks sold, mathematically;

x + y = 300 ..........(I)

Now let’s look at the prices.

x number of hotdogs sold at $2, this give a total of $2x hotdogs

y number of hamburgers sold at $3, this give a total of $3y.

Adding both to give total, we have ;

2x + 3y = 780.......(ii)

This means we have two equations to solve simultaneously. From equation 1, we can say x = 300 -y

Now let’s insert this in the second equation;

2(300-y) + 3y = 780

600-2y + 3y = 780

y = 780-600 = 180

Recall; x + y = 300

x = 300 -y

x = 300-180 = 120

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3 years ago
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