All categories

4 years ago

2x – 4 = 6 The answer is 10, but I just need a step by step explanation for this

Mathematics

2 answers:

Bezzdna [24]4 years ago

8 0

Answer:

Step-by-step explanation:

2x−4=6

Step 1: Add 4 to both sides.

2x−4+4=6+4

2x=10

Step 2: Divide both sides by 2.

2x/2=10/2

x=5

vazorg [7]4 years ago

6 0

Answer:

x=5

Step-by-step explanation:

2x – 4 = 6

Add 4 to each side

2x – 4 +4= 6+4

2x = 10

Divide each side by 2

2x/2 = 10/2

x = 5

You might be interested in

A circle has a diameter of 40 in. Find the circumference of the circle to the nearest tenth. Use 3.14 for pi .

insens350 [35]

Answer: something is wrong circumference is solved by pi times the diameter or pi times the radius times 2

40 x 3.14 = 125.6

Step-by-step explanation:

Sorry man

6 0

3 years ago

I need helpppppppppppppppppppp

Ostrovityanka [42]

Answer:

Step-by-step explanation:

4 0

3 years ago

Need help with this

maw [93]

Answer:

0, 5/4

Step-by-step explanation:

If $k=0$ , you get 0=0, which is obviously true.

As long as K is not 0, you can divide by k and get $4k=5$ which is solved by $k=5/4$

6 0

4 years ago

Order the numbers from least (top) to greatest (bottom). Move to Bottom -9 |-6| |-5| -4 |-3| |-2| |1

pav-90 [236]

Answer:

-9, -4, 1, |-2|, |-3|, |-5|, |-6|

Step-by-step explanation:

Absolute value | | makes the number positive

7 0

3 years ago

Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and th

andrew11 [14]

Answer:

a) 0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b) 0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c) 0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 8.1 minutes and a standard deviation of 2.0 minutes.

This means that $\mu = 8.1, \sigma = 2$

a. between 5 and 10 min

This is the p-value of Z when X = 10 subtracted by the p-value of Z when X = 5.

X = 10

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10 - 8.1}{2}$

$Z = 0.95$

$Z = 0.95$ has a p-value of 0.8289

X = 5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5 - 8.1}{2}$

$Z = -1.55$

$Z = -1.55$ has a p-value of 0.0606

0.8289 - 0.0606 = 0.7683

0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b. less than 5 min

p-value of Z when X = 5, which, found from item a, is of 0.0606

0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c. more than 10 min

1 subtracted by the p-value of Z when X = 10, which, from item a, is of 0.8289

1 - 0.8289 = 0.1711

0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

7 0

3 years ago