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3 years ago

7.The mass of a grain of sand is approximately 2.8×10^−11 grams

Mathematics

2 answers:

ZanzabumX [31]3 years ago

8 0

The Answer is A. Milligram.

Mazyrski [523]3 years ago

3 0

Answer :- A) Milligram is the right answer.

Explanation:-

The mass of a grain of sand is approximately $2..8\times10^{-11}\text{ grams}$

We know that 1 gram=1,000 milligrams

Therefore,The mass of a grain of sand is approximately $=2.8\times10^{-11}\times1000\text{ milligram}\\=2.8\times10^{-11}\times10^3\text {milligram}\\=2.8\times10^{-11+3}\text{ milligram}....\text{[by using law of exponents]}\\=2.8\times10^{-8}\text{ milligram}$

Thus, the mass of a grain of sand is approximately $2.8\times10^{-8}\text{ milligram}.$

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Andreas93 [3]

Use formula $a^2-2ab+b^2=(a-b)^2$

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6 0

3 years ago

Read 2 more answers

The number of views on an interesting video after it's uploaded is represented by the following table:

defon

Answer:

The model for V(t) ,the number of views, t ,months after it's uploaded, best fits the data is $,V(t)=50(6.25)^t$

Step-by-step explanation:

Time (months) Views

0 50

2 313

4 1950

6 12,210

8 76,300

10 476,800

$(x_1,y_1)=(0,50)\\(x_2,y_2)=(2,313)\\(x_3,y_3)=(4,1950)$

$Slope = \frac{y_2-y_1}{x_2-x_1}$

$Slope = \frac{313-50}{2-0}$

Slope =131.5

$Slope = \frac{y_3-y_2}{x_3-x_2}$

$Slope = \frac{1950-313}{4-2}$

Slope =818.5

Since the slope is not same . So, it is not a linear relationship

$\frac{y_2}{y_1}=\frac{313}{50}=6.25\\\frac{y_3}{y_2}=\frac{1950}{313}=6.25$

Since the ratio between the consecutive outputs is same so, it is exponential relationship.

Formula : $y=ab^t$

Where a is the initial value = 50

b = rate of change = 6.25

The model for V(t) ,the number of views, t ,months after it's uploaded, best fits the data

So $,V(t)=50(6.25)^t$

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2 years ago

Write an inequality to represent the graph. a dashed line passing through points 0 comma negative 3 and 2 comma 2 with shading a

scZoUnD [109]

Answer: y > (5/2)*x - 3

Step-by-step explanation:

Ok, the thins we should notice.

The line is shaded, so the values of the line are not solutions of the inequality, then we should use < or >.

The shaded part is above the line, so we have:

y > a*x + b.

A linear relationship can be written as:

f(x) = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

Now, we know that our line passes through the points (0, -3) and (2, 2)

Then the slope is:

a = (2 -(-3))/(2 - 0) = 5/2.

f(x) = (5/2)*x + b.

To find the value of b, we can replace the values of one of the points in the equation, let's use the point (0, -3)

f(0) = -3 = (5/2)*0 + b

-3 = b

Then the line is:

f(x) = (5/2)*x - 3

Then the inequality is:

y > (5/2)*x - 3

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olga nikolaevna [1]

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PilotLPTM [1.2K]

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