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svlad2 [7]
3 years ago
7

In ΔVWX, the measure of ∠X=90°, VX = 35, XW = 12, and WV = 37. What is the value of the cosine of ∠W to the nearest hundredth?

Mathematics
2 answers:
devlian [24]3 years ago
8 0

<u>Given</u>:

Given that VWX is a right triangle.

The measure of ∠X is 90°

The length of VX = 35, XW = 12, and WV = 37.

We need to determine the value of cosine of ∠W.

<u>Value of cosine of ∠W:</u>

The value of cosine of ∠W can be determined using the trigonometric ratio.

Thus, we have;

cos \ W=\frac{adj}{hyp}

Substituting \theta=W, the side adjacent to W is XW and hypotenuse is WV

Thus, we get;

cos \ W=\frac{XW}{VW}

Substituting XW = 12 and WV = 37, we have;

cos \ W=\frac{12}{37}

cos \ W=0.324

     W=cos ^{-1}(0.324)

     W=71.09^{\circ}

Thus, the value of cosine of ∠W is 71.09°

Natalka [10]3 years ago
3 0

Answer:

Cosine W = 0.32

Step-by-step explanation:

Adj/Hypo = 12/37 = 0.3243 = 0.32

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