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jekas [21]
3 years ago
14

By applying styles formats are being applied ?

Computers and Technology
2 answers:
Dovator [93]3 years ago
7 0

Answer:

A

Explanation:

The same formats are being applied.

VikaD [51]3 years ago
5 0

Answer:

A

Explanation:

Let's take the letters in a keyboard. If I were to type a document; there are several word format I can chose like Calibre, Times New Roman, Gothic etc. However for each word format I can make the words bold or italicized which are styles.

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What are some elements commonly included in forms in Word? Check all that apply.
MArishka [77]

Answer:

dates

text

drop-down lists

8 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
The connectors on the computer allow you to plug in devices such as keyboards and printers. what are these called?
madam [21]
USB port. That allows you to plug in devices.
8 0
3 years ago
In this problem, you will write three methods to:
gulaghasi [49]

Answer:

see explaination for program code

Explanation:

program code below:

class Names{

public static String[] makeNames(String[] array1, String[] array2){

if(array1.length == 0) return array2;

if(array2.length == 0) return array1;

String[] res = new String[array1.length*array2.length];

int k = 0;

for(int i=0;i<array1.length;i++){

for(int j=0;j<array2.length;j++){

res[k++] = array1[i] + " " + array2[j];

}

}

return res;

}

public static String[] makeNames(String[] array1, String[] array2, String[] array3){

return makeNames(makeNames(array1, array2), array3);

}

public static void print(String[] array){

for(String name : array){

System.out.println(name);

}

}

public static void main(String[] args) {

String[] first = {"David", "Mike", "Katie", "Lucy"};

String[] middle = {"A","B", "C", "D", "E"};

String[] last = {};

String[] names = makeNames(first, middle, last);

print(names);

print(names);

}

}

8 0
3 years ago
Next, Sue decides to embed a chart from Microsoft Word. She copies and pastes data from a table that she has already created in
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Answer:

Its D

Explanation:

On Edg

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