Answer:
iSCSI Qualified Name (IQN).
Explanation:
iSCSI is simply an acronym for Internet Small Computer Systems Interface and it is typically an internet protocol (IP) with respect to a storage area network (SAN) standard used essentially for connecting data storage facilities over a transmission control protocol and internet protocol (TCP/IP).
iSCSI Qualified Name (IQN) is a type of iSCSI name that requires a registered domain name to generate a unique iSCSI identifier.
This ultimately implies that, a data storage organization must have a registered domain name in order to be able to generate an iSCSI Qualified Name (IQN). Also, the iSCSI Qualified Name (IQN) is not linked to an internet protocol (IP) address and as such it is considered to be a logical name.
Answer:
Answered below
Explanation:
//Program is written in Python
sum = 0
def sum_of_values(dict_data, number_of_boys):
for dict in dict_data:
for key in dict.keys():
if key == number_of_boys:
sum += dict[key]
//After looping check the sum variable and //return the appropriate value.
if sum != 0:
return sum
elif sum == 0:
//There was no key of such so no addition.
return 0
Answer:
Comodo's virus removal software automatically detects different type of malware. Comodo Anti malware has a built-in fully featured malware scanner that can track and remove the virus, hidden files, rootkits, and malicious registry keys embedded deep in your system files.
Explanation:
have a bless day
<span>Answer - Hotspots</span>
<span>
</span>
<span>Public places where you can wirelessly
connect to the internet are known as Wi-Fi hotspots. Common Wi-Fi hotspot locations
(where wireless internet connection is offered) include such places as cafes,
hotels, airports, and libraries. These businesses usually create hotspots for
the use of their customers.</span>
Answer:
Answer D : Low is 4 and high is 6
Explanation:
Here is Function
int binarySearch(int arr[], int l, int r, int x) {
while (l <= r) {
int m = l + (r - l) / 2;
// Check if x is present at mid
if (arr[m] == x)
return m;
// If x greater, ignore left half
if (arr[m] < x)
l = m + 1;
// If x is smaller, ignore right half
else
r = m - 1; }
// if we reach here, then element was
// not present
return -1; }