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3 years ago

Personality theorists often focus on ________________.

Physics

1 answer:

raketka [301]3 years ago

8 0

Personality theorists often focus on differences in individuals.

Answer: Option A

Explanation:

According to the personality psychology, personality scientists study personality and its variations amongst the individuals. They often focus on the thoughts, judgements and social behaviour of the individuals that they exhibit over time. With these observations, they form a report which better conclude their mental and emotional state.

By studying different types of personalities and respective behaviour, personality theorists are able to predict the diversity in human nature and that whether a person is mentally and emotionally healthy. If not, theorists conduct therapies to get them in order and hence, lead a more meaningful and healthy life.

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By what percent does the braking distance of a car decrease, when the speed of the car is reduced by 10.3 percent? Braking dista

likoan [24]

The braking distance is the distance traveled by a car experiencing a braking force until it comes to rest.

Our initial energy is solely kinetic:
$E_i = \frac{1}{2}mv^2$

And, since the car goes to rest, it is no longer in motion. It will have no kinetic energy.
$E_f = 0$

Therefore, there was work done by the braking force.

$W_B = E_f - E_i = -\frac{1}{2}mv^2$

Recall the definition of work:
$W = F\cdot \Delta x$

Or in this case, since the displacement and breaking force are antiparallel:
$W = -F_B\Delta x$

This is equivalent to the dissipation of kinetic energy:
$W = -F_B\Delta x = -\frac{1}{2}mv^2$

Now, to visualize this, let's rearrange the equation to solve for displacement.

$\Delta x =\frac{mv^2}{2F_B}$

There is a direct, SQUARE relationship between necessary braking distance speed.

If the speed was reduced by 10.3 percent, its new speed is only 89.7% percent of the original, so:
$\Delta x' =\frac{m(0.897v)^2}{2F_B}$

$\Delta x' = 0.8046\Delta x$

The reduction by a percentage is:
$1 - 0.8046 = 0.1954 \\\\\boxed{= 19.54\%}$

6 0

2 years ago

If an object is projected horizontally from a height of 5 m with an initial velocity of 7 m/s, what is the value of x0?

tatiyna

ANSWER IS D X0=9.8m/s^2

5 0

2 years ago

A reasonable estimate of the moment of inertia of an ice skater spinning with her arms at her sides can be made by modeling most

Oxana [17]

Answer:

A) $I_{total}$ = 1.44 kg m², B) moment of inertia must increase

Explanation:

The moment of inertia is defined by

I = ∫ r² dm

For figures with symmetry it is tabulated, in the case of a cylinder the moment of inertia with respect to a vertical axis is

I = ½ m R²

A very useful theorem is the parallel axis theorem that states that the moment of inertia with respect to another axis parallel to the center of mass is

I = $I_{cm}$ + m D²

Let's apply these equations to our case

The moment of inertia is a scalar quantity, so we can add the moment of inertia of the body and both arms

$I_{total}$ = $I_{body}$ + 2 $I_{arm}$

$I_{body}$ = ½ M R²

The total mass is 64 kg, 1/8 corresponds to the arms and the rest to the body

M = 7/8 m total

M = 7/8 64

M = 56 kg

The mass of the arms is

m’= 1/8 m total

m’= 1/8 64

m’= 8 kg

As it has two arms the mass of each arm is half

m = ½ m ’

m = 4 kg

The arms are very thin, we will approximate them as a particle

$I_{arm}$ = M D²

Let's write the equation

$I_{total}$ = ½ M R² + 2 (m D²)

Let's calculate

$I_{total}$ = ½ 56 0.20² + 2 4 0.20²

$I_{total}$ = 1.12 + 0.32

$I_{total}$ = 1.44 kg m²

b) if you separate the arms from the body, the distance D increases quadratically, so the moment of inertia must increase

6 0

4 years ago

Find the coefficient of kinetic friction μk. express your answer in terms of some or all of the variables d1, d2, and θ.

Andre45 [30]

internet tension = mass * acceleration internet tension = 23 – Friction tension = 14 * acceleration Friction tension = µ * 14 * 9.8 = µ * 137.2 23 – µ * 137.2 = 14 * acceleration Distance = undemanding speed * time undemanding speed = ½ * (preliminary speed + very final speed) Distance = ½ * (preliminary speed + very final speed) * time Distance = 8.a million m, preliminary speed = 0 m/s, very final speed = a million.8 m/s 8.a million = ½ * (0 + a million.8) * t Time = 8.a million ÷ 0.9 = 9 seconds Acceleration = (very final speed – preliminary speed) ÷ time Acceleration = (a million.8 – 0) ÷ 9 = 0.2 m/s^2 23 – µ * 137.2 = 14 * 0.2 resolve for µ

6 0

3 years ago

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Jimena is stopped at a red light. When the light turns green, she

Ludmilka [50]

First one accelerated

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3 years ago