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kari74 [83]
2 years ago
8

A wave which needs a medium (solid, liquid, gas) in order to propagate itself.

Physics
2 answers:
Vadim26 [7]2 years ago
5 0

The correct answer to the question is: Sound wave.

EXPLANATION:

Before going to answer this question, first we have to understand longitudinal wave.

A longitudinal wave is a mechanical wave in which the direction of propagation of wave is parallel to the direction of particle vibration.

This wave propagates through a medium in the form of compression and rarefaction.

Compression are the regions of high pressure zones where the particles of the medium are closely aggregated to each other.

Rarefaction is the region of low pressure where particles of the medium are not so close to each other as compared to compression.

The longitudinal wave can not propagate in space. It always needs a medium for it's propagation. The medium may be solid, liquid or gas .

For instance, sound wave is a longitudinal wave.

Hence, the correct answer of this question is sound wave which needs a medium for it's propagation.

kherson [118]2 years ago
5 0

Answer:

Longitudinal waves

Explanation:

Mechanical waves are those waves which require medium to propagate. It has two types:

i) Transverse waves: These waves depend upon the rigidity of the medium so, they can propagate though solids and liquids but cannot pass through gases.

ii)  Longitudinal waves: These waves depend upon the volume elasticity of the medium so, they can propagate through solids, gases, and liquids

Hence, the right answer is longitudinal waves.

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nexus9112 [7]

Answer:

A

Explanation:

KE = 1/2 mv^2

=1/2(30kg)( 3.4 m/s)^2

=173.4 joules

=1.7×10^2 joules

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2 years ago
Identify one harmful environmental change that occurs when a volcano erupts.
klasskru [66]
Many ecosystems and plants are damaged or destroyed when a volcano erupts.
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3 years ago
(b) Two containers made of insulating material contain the same volume of water at room
masha68 [24]

Answer:

the volume of liquid decreased due to evaporation from the exposed free surface of water so molecules got evaporated .

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5 0
2 years ago
Three crates with various contents are pulled by a force Fpull=3615 N across a horizontal, frictionless roller‑conveyor system.
SIZIF [17.4K]

The question is incomplete. Here is the complete question.

Three crtaes with various contents are pulled by a force Fpull=3615N across a horizontal, frictionless roller-conveyor system.The group pf boxes accelerates at 1.516m/s2 to the right. Between each adjacent pair of boxes is a force meter that measures the magnitude of the tension in the connecting rope. Between the box of mass m1 and the box of mass m2, the force meter reads F12=1387N. Between the box of mass m2 and box of mass m3, the force meter reads F23=2304N. Assume that the ropes and force meters are massless.

(a) What is the total mass of the three boxes?

(b) What is the mass of each box?

Answer: (a) Total mass = 2384.5kg;

               (b) m1 = 915kg;

                   m2 = 605kg;

                   m3 = 864.5kg;

Explanation: The image of the boxes is described in the picture below.

(a) The system is moving at a constant acceleration and with a force Fpull. Using Newton's 2nd Law:

F_{pull}=m_{T}.a

m_{T}=\frac{F_{pull}}{a}

m_{T}=\frac{3615}{1.516}

m_{T}=2384.5

Total mass of the system of boxes is 2384.5kg.

(b) For each mass, analyse each box and make them each a free-body diagram.

<u>For </u>m_{1}<u>:</u>

The only force acting On the m_{1} box is force of tension between 1 and 2 and as all the system is moving at a same acceleration.

m_{1} = \frac{F_{12}}{a}

m_{1} = \frac{1387}{1.516}

m_{1} = 915kg

<u>For </u>m_{2}<u>:</u>

There are two forces acting on m_{2}: tension caused by box 1 and tension caused by box 3. Positive referential is to the right (because it's the movement's direction), so force caused by 1 is opposing force caused by 3:

m_{2} = \frac{F_{23}-F_{12}}{a}

m_{2} = \frac{2304-1387}{1.516}

m_{2} = 605kg

<u>For </u>m_{3}<u>:</u>

m_{3} = m_{T} - (m_{1}+m_{2})

m_{3} = 2384.5-1520.0

m_{3} = 864.5kg

8 0
3 years ago
how much force is needed to cause a 15 kilogram bike to accelerate at a rate of 10 meters per second?
egoroff_w [7]
F = m*a, mass times acceleration.

F = 15*10 = 150 N
8 0
3 years ago
Read 2 more answers
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