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Rus_ich [418]
3 years ago
9

Kendra went on vacation for a week. When she returned home she couldn't run as far as she could before. Which principle of exerc

ise describes this?
Physics
1 answer:
pychu [463]3 years ago
8 0

Answer:

Reversibility principle of exercise

Explanation:

Kendra went on vacation for a week, meaning she stopped exercise for a week, and due to this, her body readjusts to what is demanded (rest) making her unable to run as far as she could before when she resumed training. It is now clear she has lost some of her physical skills and this effect is mostly seen when sprinters mostly lose their muscular endurance before losing other skills when they stop training for some days/weeks/months, and this is an example of the reversibility principle of exercise.

                                     

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You are given two converging lenses to build a compound microscope. Lens A has focal length 0.50 cm and lens B has focal length
siniylev [52]

Answer:

The lens to be used for the objective is lens A

Explanation:

The objective of a compound microscope

The focal length of the lens used for the objective = 1/(magnification obtained)

The focal length of most modern is equal to the tube length

The range of sizes for the focal length of a microscope is between 2 mm and 40 mm

Therefore, the appropriate lens to be used for the objective of the compound is lens A that has a focal length of 0.50 cm = 5 mm

6 0
3 years ago
If a hiker that weighs 600 newtons climbs a 50 meter hill, how much gravitational potential energy has the hiker gained?
Illusion [34]

The gravitational potential energy U is defined as the product of mass m, the acceleration of gravity g and the height of object h.

U = mgh

We do not have the mass of the hiker. But we know that its W weight is:

W = mg

Where

g = 9.8 m/s^2

So:

m = \frac{W}{g}\\\\m = \frac{600}{g}.

So:

U = (\frac{600}{g})gh\\\\U = (600N)(50m)

U = 30000J

The hiker has gained 30,000 J of energy

6 0
3 years ago
A ball is thrown horizontally from a platform so that the initial height of the ball is 6.0 m above the level ground below. The
solniwko [45]
We can first obtain time of flight from vertical fall
Initial velocity U=0, d = 6 m, a = 9.8 m/s² 
d = ut + 1/2 at²
6.0 = 0 + (1/2 × 9.80 t²) 
t = √(12/9.8)
 = 1.106 sec
Horizontal velocity = Vh = Dh/t
  = 24.0 /1.106 s
  = 21.69 m/s
The ball was thrown at a speed of 21.69 m/s
5 0
4 years ago
The position of a ball as a function of time is given by
Andre45 [30]

Answer:

x = -6.5 meters

Explanation:

The position of a ball as a function of time t is given by :

x=3\ m+(-5\ m/s)t..................(1)

Where t is time in seconds

We need to find the position of the ball at 1.9 s. It can be simply calculated putting t = 1.9 s in equation (1) as :

x=3+(-5)(1.9)

x = -6.5 meters

So, the position of the ball at 1.9 seconds is -6.5 meters. Hence, this is the required solution.

6 0
4 years ago
A race card drives one lap around a race track that is 500 meters in length. How is this displacement different from the distanc
gulaghasi [49]

Answer:

Distance is 500 m, displacement is 0

Explanation:

Distance and displacement are defined in two different ways:

- Distance is the total length of the path covered by an object in motion - so it depends on the path taken. In this problem, the distance travelled by the car corresponds to the length of one lap, which is the length of the track, so 500 m

- Displacement is the distance in a straight line between the final point and the initial point of the motion. This means that displacement does not depend on the path taken, but only on the starting and ending point of the motion. In this problem, the car completes one lap, so the final position of the car is equal to its starting position - therefore the displacement is zero, since the distance between these two points is zero.

5 0
3 years ago
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