A uniform beam of arbitrary, unsymmetrical cross-section and length 2???? is built-in at one end and simply supported in the ver
1 answer:
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<h2>Answer</h2>
The answer to this question is
As we know that accelartion is the rate of change of velocity. So, it can be write as
where
is the final velocity
is the initial velocity
t is the time
a is the accelartion
as we konw
t = ?
From rest So,
= 0
Putting values
So, the right answe is
Heya!!
For calculate velocity, lets applicate formula
<u>Δ Being Δ</u>
d = Distance = 3790 m
t = Time = 249 s
v = Velocity = ?
⇒ Let's replace according the formula and clear "v":
⇒ Resolving
Result:
The velocity is <u>15,22 meters per second.</u>
Good Luck!!
Answer
given,
wavelength = λ = 18.7 cm
= 0.187 m
amplitude , A = 2.34 cm
v = 0.38 m/s
A) angular frequency = ?
angular frequency ,
ω = 2π f
ω = 2π x 2.03
ω = 12.75 rad/s
B) the wave number ,
C)
as the wave is propagating in -x direction, the sign is positive between x and t
y ( x ,t) = A sin(k x - ω t)
y ( x ,t) = 2.34 x sin(33.59 x - 12.75 t)