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creativ13 [48]
3 years ago
11

A pyramid has a base off 100 m^2 and a height of 60 m. What is the volume of the pyramid?

Mathematics
1 answer:
scoray [572]3 years ago
7 0
V=2000m³it is b........

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Select the correct answer.
Nataly [62]

Answer:

D. Part of the solution region includes a negative number of erasers purchased; therefore, not all solutions are viable for the given situation.

Step-by-step explanation:

I got it right on the practice

7 0
3 years ago
Can you help me please.
Kamila [148]

9514 1404 393

Answer:

  a.  (-1/2, 5)

Step-by-step explanation:

The coefficients of x have opposite signs, so the x-terms can be eliminated by adding the two equations.

  (2y -12x) +(3y +12x) = (16) +(9)

  5y = 25 . . . . . . simplify

  y = 5 . . . . . . . . .divide by 5

This matches only answer choice A.

__

<em>Check</em>

The other part of answer choice A is x = -1/2. We can test this to make sure it works:

  2(5) -12(-1/2) = 16

  10 + 6 = 16 . . . . . . true, the selected answer works OK

5 0
2 years ago
What fraction of this shape is shaded?
Lilit [14]
15% it’s running
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5 0
1 year ago
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
2 years ago
Please!!! Follow me<br>_/(•_•)\_​
Vikki [24]

Answer:

Why

Step-by-step explanation:

How do I follow I'm new to dis

7 0
3 years ago
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