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3 years ago

Order of Operations- -6+(-30) divided by 5-(-2). Explain step by step

Mathematics

1 answer:

Reil [10]3 years ago

7 0

Answer:

-36/7 or -5.14287

Step-by-step explanation:

so I would get rid of parentheses you do not need them

$\frac{-6+-30}{5--2}$ = $\frac{-36}{7}$ (because when two negative come before two numbers like -x-y they are being added but negative is present to the result of the sum, when one negative sign comes after a number and the other negative sign comes before a number, like x--y they are being added as well but negative is not present to the result of the sum)

-36/7=-5.1428

hope this helps!

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Which of the following expressions is equivalent to a3 + b3?

lubasha [3.4K]

ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
${(a + b)}^{3}$
Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Which lines are perpendicular to the line y – 1 = (x+2)? Check all that apply.

Ilya [14]

Answer:

none of them

Step-by-step explanation:

Two lines are perpendicular when satisfy the next equation: m1*m2 = -1, where m1 and m2 are the slopes o the lines.

line 1:

y – 1 = (x+2)

y = x + 3

slope of line 1 = 1

line 2:

y + 2 = –3(x – 4)

y + 2 = -3*x + 12

y = -3*x + 10

slope of line 2 = -3

m1*m2 = 1*(-3 ) = -3

They are not perpendicular

line 3:

y − 5 = 3(x + 11)

y − 5 = 3*x + 33

y = 3*x + 38

slope of line 3 = 3

m1*m3 = 1*3 = 3

They are not perpendicular

line 4:

y = -3x –

slope of line 4 = -3

m1*m4 = 1*(-3 ) = -3

They are not perpendicular

line 5:

y = x – 2

slope of line 5 = 1

m1*m5 = 1*1 = 1

They are not perpendicular

line 6:

3x + y = 7

y = -3x + 7

slope of line 6 = -3

m1*m6 = 1*(-3 ) = -3

They are not perpendicular

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saul85 [17]

You need to multiply the two numbers. Or you can use long addition.

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Which of the following equations has the given solution set?

tester [92]

-2m + 5 = 2m + 5
2m + 2m = 5 - 5
4m = 0
m = 0

-2m + 5 = -2m + 5
-2m + 2m = 5 - 5
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-2m + 5 = -2m - 5
-2m + 2m = 5 + 5
0 = 10
Solution set is Ф
The third equation is the correct answer.

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