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serious [3.7K]
3 years ago
5

12 x 1/5= ? I got 12 1/5 is that correct?

Mathematics
2 answers:
coldgirl [10]3 years ago
5 0
When you're multiplying any number times a fraction with a numerator of one, that number becomes the numerator. For example:

a x 1/b = a/b

So, in your case:

12 x 1/5 = 12/5
Harlamova29_29 [7]3 years ago
3 0
Yes that is correct 
or in a mixed number it would be 61/5.
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200

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Identify the statement that uses the verb mood in the interrogative. will give brainliest
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When mindy went to China, she exchanged $1.00 for 6.589 yuan . What digit is in the tenths place and the hundredth place of 6.58
jenyasd209 [6]

Answer:

tenth place= 5

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6 0
3 years ago
Pilates is a popular set of exercises for the treatment of individuals with lower back pain. The method has six basic principles
Bas_tet [7]

Answer:

a) We reject H₀     We find difference between the mean of the two groups

b) we accept H₀ : There is no statistical difference  ( in the scale of pain) when the difference in samples means is 1

Step-by-step explanation:

Group 1: Only with educational material

Sample size     n₁  =  42

Sample mean   x₁  =  3,2

Sample standard deviation  s₁  =  2,3

Group 2: With exercises with the treatment of individuals

Sample size    n₂   =  42

Sample mean    x₂  = 5,2  

Sample standard deviation   s₂  = 2,3

Test Hypothesis

Null Hypothesis                     H₀           x₂  -  x₁  = 0  or    x₁  =  x₂

Alternative Hypothesis         Hₐ           x₂  -  x ₁ > 0  or    x₂  >  x₁

Significance level  α  = 0,01

Sample sizes are n₁  =  n₂  >  30

We use z-test

for α  = 0,01     z(c)  ≈  2,32

To calculate z(s)

z(s)  =  (  x₂  -  x₁ ) / √ (2,3)²/42  + (2,3)²/42

z(s)  = ( 5,2  -  3,2 )/ √0,2519

z(s)  =  2 / 0,5

z(s) = 4

Comparing  z(s)  and z(c)

z(s) > z(c)

z(s) is in the rejection region. We reject H₀ the true average pain level for the control condition exceeds that for the treatment condition.

b) Does the true average pain level for the control condition exceed that for the treatment condition by more than 1.

In this case

z( s) =  x₂ - x₁ / 0,5

z(s) =  1 /0,5

z(s) = 2

Comparing z(s) and z(c)  now

z(s) < z(c)        2 < 2,32

And z(s) is in the acceptance region ( for the same significance level) and we should accept H₀  equivalent to say that the two groups statistical have the same mean

5 0
3 years ago
Which relation is a function?
sergejj [24]

To determine which relation is a function, we can perform something called the vertical line test. We cover the graph in repeating vertical lines and if one vertical line connects with more than one point of the relation, the relation is not a function.

The relation in the bottom right corner is the only relation that passes the vertical line test.

7 0
3 years ago
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