A $310 suit is marked down by 10%. Find the sales price.

How can you use 260 divided by 13 to help you find 286 divided by 13

Alexeev081 [22]

Answer:

Well, 260 divided by 13 is 20.

286-260=26

And 26 divided by 13 is 2.

Step-by-step explanation:

So there's that-

Brainliest??

4 0

3 years ago

Oil leaked from a tank at a rate of r(t) liters per hour. the rate decreased as time passed, and values of the rate at two hour

Galina-37 [17]

The given data is
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3

The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.

The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.

The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L

The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L

Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L

4 0

3 years ago

Read 2 more answers

Find the measure of TRS

nignag [31]

Answer: The sum of the measures of the angle inside of a triangle add up to 180 degrees. That's all we're doing over here. And so let's see if we can simplify this a little bit. So these two guys-- 90 plus 90's going to be 180, so you get 180 minus theta …

Author: Sal Khan

Step-by-step explanation:

4 0

3 years ago

BRAINLIEST ✨

inna [77]

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6Common ratio: 4/(8/3) = 3/2 same as 6/4 = 3/2. Correct.

Step-by-step explanation:

Am I right? just commet if I'm wrong

then TANKYOU>^_^<!

7 0

2 years ago

A park has a 333 meter (\text{m})(m)left parenthesis, start text, m, end text, right parenthesis tall tether ball pole and a 6.8

dybincka [34]

Answer:option B & D are correct

Step-by-step explanation:

Given options are

A B C D E

Tether ball pole shadow 1.35 1.8 3.75 0.6 2

Flagpole shadow 3.4 4.08 8.35 1.36 4.8

Ratio of corresponding height & shadows should be same

3 meter tall tether ball pole and a 6.8 tall flagpole

=> Ratio = 6.8/3 = 68/30 = 34/15

A - 3.4/1.35 = 340/135 ≠ 34/15( 306/135)

B - 4.08/1.8 = 408/180 = 34/15 = 34/15 ( Correct option)

C 8.35/3.75 = 835/375 = 167/75 ≠ 34/15( 170/75)

D 1.36/0.6 = 136/60 = 34/15 = 34/15 ( Correct option)

E 4.8/2 = 48/20 = 12/5 = 36/15 ≠ 34/15

option B & D are correct

6 0

3 years ago

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