The law of sines can be used to solve this. We have two sides of a triangle and the angle opposite one of them. We want to find the angle opposite the other known side.

In the attached, the triangle is ΔACS. We have side "a" = 9, and side "c" = 10. Angle A is given as 64°. The law of sines tells us ...

sin(C)/c = sin(A)/a

sin(C) = (c/a)sin(A)

C = arcsin((c/a)sin(A)) = arcsin(10/9·sin(64°)) ≈ 87.03°

The ladder makes an angle of about 87° with the ground.

3 0

3 years ago

Find the value of tangent for angle A

gavmur [86]

AC = √(40²-12²) = √(1600-144) = √1456 = 4√91

tanA = 12/4√91 = 3/√91 = 3√91/91

option а.

4 0

4 years ago

Read 2 more answers

The graph of y = tan ⁡(x − π / 2) compared to the graph of y = tan ⁡x has:

vodomira [7]

Answer:

Last Option moved $\frac{\pi}{2}$ units right

Step-by-step explanation:

If we have a function f(x) and we want to move it horizontally then we make the transformation:

$y = f (x + h)$

If $h$ then the graph of f(x) moves horizontally h units to the right

If $h> 0$ then the graph of f(x) moves horizontally h units to the left.

In this case we have the function $y = tan (x)$ and the transformation is performed to obtain $y = tan(x- \frac{\pi}{2})$

Notice that in this transformation

$h$

<u><em>Then the graph of $y = tan (x)$ moves horizontally $\frac{\pi}{2}$ to the right</em></u>

5 0

3 years ago