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oksian1 [2.3K]
3 years ago
15

What is the decimal number 8 53/100

Mathematics
2 answers:
kvv77 [185]3 years ago
5 0
\frac{53}{100}=0.53 \\ 
 \\ 8=8 \\ 
 \\ Solution:8.53 

Alexandra [31]3 years ago
4 0
8.53, because 8 is a whole number so it stays there. The 53/100 would be .53 because 53/100 is fifty three hundredths so you put it into the hundredths place.
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What is being constructed based on the markings in the following diagram?
Liula [17]

Answer:

  perpendicular line through a point on a line

Step-by-step explanation:

The circle centered at C seems intended to produce point D at the same distance as point B. That is, C is the midpoint of BD.

The circles centered at B and D with radius greater than BC seems intended to produce intersection points G and H. (It appears accidental that those points are also on circle C. As a rule, that would be difficult to do in one pass.)

So. points G and H are both equidistant from points B and D. A line between them will intersect point C at right angles to AB.

Segment GH is perpendicular to AB through point C (on AB).

6 0
3 years ago
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What is the slope of a line that passes through the two points (12, -18) and (11,12)
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The slope is -30 because when u calculate the rise over run it gets to -30
7 0
2 years ago
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Please help!!!! ASAP giving brainiest
mariarad [96]

Answer:

JK=2.25\ units

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor

so

\frac{JK}{ST}=\frac{KL}{TU}

substitute the given value and solve for JK

\frac{JK}{1.5}=\frac{6}{4}

JK=(1.5)\frac{6}{4}

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8 0
2 years ago
Kyra observed that 85% of the students at a library liked reading mystery stories. If 30 students at the library did not like re
UkoKoshka [18]
It is said that 85% of the students liked reading mystery stories. This means the remaining 15% don't like to read these stories. If there are 30 students belonging to the second category, then the number of students who liked reading mystery stories is (30/0.15)*0.85 equal to 170 students out of 200 students.
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2 years ago
State whether f is a function
Alenkinab [10]
<h2>Answer:</h2>

y=\pm (\frac{x}{6})^{\frac{1}{4}} \ is \ not \ a \ function

<h2>Step by step solution:</h2>

A function f from a set A to a set B is a relation that assigns to each element x in the set A exactly one element y in the set B. The set A is the domain (also called the set of inputs) of the function and the set B contains the range (also called the set of outputs). On the other hand, a function has an inverse function if and only if passes the Horizontal Line Test for Inverse Functions. This test tells us that a function f has an inverse function if and only if there is no any horizontal line that intersects the graph of f at more than one point. So the function is called one-to-one. The graph of f is shown below. As you can see, this function does not pass the Horizontal Line Test, therefore the inverse is not a function. However, let's find f^-{1}(x):

f(x)=6x^4 \\ \\ Substitute \ f(x) \ by \ y \\ \\ y=6x^4 \\ \\ Interchange \ x \ and \ y: \\ \\ x=6y^4 \\ \\ Solve \ for \ y: \\ \\ y^4=\frac{x}{6} \\ \\ Solving \\ \\y=\pm \sqrt[4]{\frac{x}{6}} \\ \\ \boxed{y=\pm \left(\frac{x}{6}\right)^{\frac{1}{4}}}

and this is not a function because there are elements in the set of inputs that match with two elements in the set of outputs.

5 0
3 years ago
Read 2 more answers
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