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const2013 [10]
3 years ago
5

Help in 1 a-d please

Mathematics
1 answer:
MArishka [77]3 years ago
6 0
In five seconds he travels 290 feet.
In three seconds he travels 174 feet.
Yes, he is increasing time and distance at a steady rate.
Y = 58x
X representing the amount of time
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-14a-5=-12
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7 0
2 years ago
If cos 0=2/3, what are the values of sin 0 and tan 0?
morpeh [17]

Answer:

Below

Step-by-step explanation:

● cos O = 2/3

We khow that:

● cos^2(O) + sin^2(O) =1

So : sin^2 (O)= 1-cos^2(O)

● sin^2(O) = 1 -(2/3)^2 = 1-4/9 = 9/9-4/9 = 5/9

● sin O = √(5)/3 or sin O = -√(5)/3

So we deduce that tan O will have two values since we don't khow the size of O.

■■■■■■■■■■■■■■■■■■■■■■■■■

●Tan (O) = sin(O)/cos(O)

● tan (O) = (√(5)/3)÷(2/3) or tan(O) = (-√(5)/3)÷(2/3)

● tan (O) = √(5)/2 or tan(O) = -√(5)/2

4 0
3 years ago
a conical tank with vertex down is 10 feet across the top and 12 feet deep. If water is flowing out of the tank at a rate of 12
TiliK225 [7]

Answer:

The water level is dropping at a rate of 0.24 ft/s

Step-by-step explanation:

Here, we simply want to calculate the change in depth (height of the cone) , given the volume change

Mathematically, we have the volume of a cone as;

V = 1/3 * π * r^2 * h

we are given dv/dt as 12 ft^3/m

dv/dh = 1/3 * π * r^2

Substituting the value for the radius, we have

dv/dh = 1/3 * 22/7 * 4^2 = 50.29

dh/dt = dh/dv * dv/dt

dh/dv = 1/(dv/dh) = 1/50.29

Thus,

dh/dt = 1/50.29 * 12

dh/dt = 0.24 ft/s

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2 years ago
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leonid [27]
X= y(d-b) over a-c would be the answer
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How did your position affect the vital capacity of your lungs? Suggest an explanation for any difference you found .
finlep [7]

Answer:

sdf

Step-by-step explanation:

dsf

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