3x <span>≥ 20
hoped it helped</span>
To get the answer to this equation you first cancel out the 6! ;)
(x^2-1)(6x-1) / (x+1)
Then rewrite x^2-1 in the form a^2 + b^2, where a=x and b=1
(x^2-1^2)(6x-1) / (x+1)
Then use the difference of squares!
(x+1)(x-1)(6x-1) / (x+1)
LASTLY cancel "x+1" !
so ur answer is (x-1) (6x-1)
That makes the correct answer to this problem answer choice (D) (x-1) (6x-1)
YW!!! ;)
There are 1000 ml in one liter if you drank 650 ml then:
1000 - 650 = 350
350 ml are left
:)))
<h3>
Answer: 80 degrees</h3>
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Explanation:
I'm assuming that segments AD and CD are tangents to the circle.
We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.
By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.
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Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.
Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.
We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.
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Here's what we have so far for quadrilateral DAEC
- angle A = 90
- angle E = 100
- angle C = 90
- angle D = unknown
Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees
A+E+C+D = 360
90+100+90+D = 360
D+280 = 360
D = 360-280
D = 80
Or a shortcut you can take is to realize that angles E and D are supplementary
E+D = 180
100+D = 180
D = 180-100
D = 80
This only works if AD and CD are tangents.
Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.