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Umnica [9.8K]
2 years ago
7

The only soft-drink flavours available at a party were cola and

Mathematics
1 answer:
vredina [299]2 years ago
3 0

The number of guests that were at the party is 26. This was illustrated in the probability.

<h3>How to compute the probability?</h3>

From the information, it was stated that twenty six soft-drinks were consumed. Therefore, it implies that there were 26 people.

From the information, 9 guests had raspberry and 13 had cola while the remaining was shared equally. Therefore, the raspberry consumed will be 11 and 15 cola were drank.

The probability that a randomly chosen party guest had a cola drink will be:

= 15/26

The probability that a randomly chosen party guest had a raspberry drink will be:

= 11/26

The probability of the people who had both a raspberry and cola drink will be 0 since everyone had different drinks.

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

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The answer is 981.75
6 0
3 years ago
Consider the initial value function y given by
Nuetrik [128]

Answer:

y(s) = \frac{5s-53}{s^{2} - 10s  + 26}

we will compare the denominator to the form (s-a)^{2} +\beta ^{2}

s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}

comparing coefficients of terms in s

s^{2} : 1

s: -2a = -10

      a = -2/-10

      a = 1/5

constant: a^{2}+\beta ^{2} = 26

               (\frac{1}{5} )^{2} + \beta ^{2} = 26\\\\\beta^{2} = 26 - \frac{1}{10} \\\\\beta =\sqrt{26 - \frac{1}{10}} =5.09

hence the first answers are:

a = 1/5 = 0.2

β = 5.09

Given that y(s) = A(s-a)+B((s-a)^{2} +\beta ^{2} )

we insert the values of a and β

  \\5s-53 = A(s-0.2)+B((s-0.2)^{2} + 5.09^{2} )

to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A

5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)

-52 = B(26)

B = -52/26 = -2

to get A lets substitute s=0.4

5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)

-51 = 0.2A - 52.08

0.2A = -51 + 52.08

A = -1.08/0.2 = 5.4

<em>the constants are</em>

<em>a = 0.2</em>

<em>β = 5.09</em>

<em>A  = 5.4</em>

<em>B = -2</em>

<em></em>

Step-by-step explanation:

  1. since the denominator has a complex root we compare with the standard form s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}
  2. Expand and compare coefficients to obtain the values of a and <em>β </em>as shown above
  3. substitute the values gotten into the function
  4. Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
  5. after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above

Thanks...

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Answer:

6: S

7: C

8: C

9: C

10: N

11: C

12: S

13: S

14: N

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Step-by-step explanation:

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Find the volume of the square pyramid below.
miv72 [106K]

Hello!

\bf ANSWER

The volume of the square pyramid is approximately \boxed{ \bf 19.19~km^3}

____________________________________________________________

\bf EXPLANATION

V = a^{2}\frac{h}{3}

First, we must find the area of the square base.

A = l * w

A = 3.5 * 3.5

A = 12.25 km^2

The area of the base is 12.25 km^2. Now, multiply the base area by the perpendicular height. Then divide by 3.

V = (12.25 * 4.7) / 3

V = 19.1916666667

V ≈ 19.19 km^3



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