Which could be used to evaluate the expression -6(4 2/3)

Evaluate |a+b-c|, given a=5,b=-3, and c=-2

nadya68 [22]

|a+b-c| = |5+(-3)-(-2)| =|5-3+2| = |4| = 4

3 0

2 years ago

Keisha borrowed money from a bank to buy a fishing boat.

kondor19780726 [428]

Answer:

Your $19,513 loan has 60 monthly payments of $366.00 at 4.75%.

If you make all of your payments on this loan, and do not prepay any of the principal, the total interest for this loan is $2,447.26.

Step-by-step explanation:Loan Summary

Total payments $21,960.26

Total interest paid $2,447.26

Loan amount $19,513

Monthly payment $366.00

Interest rate 4.75%

Term 60 monthly payments

8 0

1 year ago

Plz help I'll give brainlest

jarptica [38.1K]

<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 $m^2$ </h3><h3>3.Area of the trapezoid = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is = 1200 square in</h3><h3>8.The area of the rhombus is =84 $cm^2$ </h3><h3>9.Area of the trapezoid = 240 square ft</h3>

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

=16× 18 square units

= 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

=(9×5) $m^2$

=45 $m^2$

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

$=\frac{1}{2} \times (12+5) \times 4$ square in.

= 34 square in.

4.

Height = 2 ft and parallel sides are 2 ft and 6 ft

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

$=\frac{1}{2} \times (2+6) \times 2$ square ft

= 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus $= \frac{1}{2}\times {\textrm{product of diagonals}$

$=\frac{1}{2 } \times 6\times 9$ square cm

= 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus $= \frac{1}{2}\times {\textrm{product of diagonals}$

$=\frac{1}{2 } \times 12\times 18$ square in

= 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

= 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = $\frac {1}{2} \times 14 \times 12$ $cm^2$

=84 $cm^2$

9.Given , the base of trapezoid are 24 ft and 16 ft and height is 12 ft

Area of the trapezoid = $\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height$

= $\frac{1}{2} \times (24+16) \times 12$ square ft

= 240 square ft

8 0

2 years ago

PLS HELP (links = report)

NARA [144]

Answer:

2040 m3

Step-by-step explanation:

you see in the pic, the shape may cut into 2 pieces, this is 1/2 of the shape.

so we take (24*10*17)/2=2040 m3.

Hope it helps you

3 0

2 years ago

Find the product of the expression:<br> (5p^3) (-1m^8p^2)

Rainbow [258]

Answer:

We conclude that:

$\left(5p^3\right)\:\left(-1m^8p^2\right)=-5p^5m^8$

Step-by-step explanation:

Given the expression

$\left(5p^3\right)\:\left(-1m^8p^2\right)$

Apply the rule:

$a\left(-b\right)=-ab$

so the expression becomes

$\left(5p^3\right)\left(-1\cdot \:m^8p^2\right)=-5p^3\cdot \:1\cdot \:m^8p^2$

Apply the rule:

$a^b\cdot \:a^c=a^{b+c}$

so the expression becomes

$=-5p^{3+2}\cdot \:1\cdot \:m^8$ ∵ $p^3p^2=p^{3+2}$

$=-5p^5\cdot \:1\cdot \:m^8$

$=-5p^5m^8$

Therefore, we conclude that:

$\left(5p^3\right)\:\left(-1m^8p^2\right)=-5p^5m^8$

7 0

2 years ago