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The area of a square is 36 square centimeters. A rectangle has the same perimeter as the square. The length of the rectangle is

Irina-Kira [14]

Answer:32sq cm

Step-by-step explanation:

area of square 36

sides are then 6 by 6

6+6+6+6=24

24 can be made into 4+4+8+8 8 is twice as much as 4 8x4=32

4 0

2 years ago

Solve S=2(lw + lh + wh) for w

vovikov84 [41]

Dividing by 2, we have S/2=lw+lh+wh. After that, we subtract lh from both sides to get S/2-lh=lw+wh. Next, we divide both sides by w to get (S/2)/w=l+h. Next, we divide by S/2 to get 1/w=(l+h)/(S/2). Lastly, we multiply by w and divide by (l+h)/(S/2) to get w=(S/2)/(l+h)

7 0

3 years ago

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The base of a solid right pyramid is a regular hexagon with a radius of 2x units and an apothem of units. A solid right pyramid

Xelga [282]

Answer:

$6 x^2*\sqrt{3}$

Step-by-step explanation:

The base of the pyramid we need to study is a hexagon.

Let's look at the attached image of an hexagon to understand how we are going to find the area of this figure.

Notice that an hexagon is the combination of 6 exactly equal equilateral triangles in our case of size "2x" (notice that the "radius" of the hexagon is given as "2x")

Therefore the area of the hexagon is going to be 6 times the area of one of those equilateral triangles.

We know the area of a triangle is the product of its base times its height, divided by 2: $\frac{base*height}{2} = \frac{2x*height}{2}$

We notice that the triangle's height is exactly what is called the "apothem" of the hexagon (depicted in green in our figure) which measures $x\sqrt{3}$ , so replacing this value in the formula above for the area of one of the triangles:

$\frac{2x*height}{2}= \frac{2x*x\sqrt{3} }{2}=x^2\sqrt{3}$

Then we multiply this area times 6 to get the total area of the hexagon (6 of these triangles):

Area of hexagon = $6x^2\sqrt{3}$

which is the last option given in the list.

5 0

3 years ago

Read 2 more answers

Is -3y = 5x + 4 perpendicular

aivan3 [116]

Answer:

no it is not perpedicular

Step-by-step explanation:

I plugged the equation into a graphing calculator and the line does not appear to be perpendicular

5 0

3 years ago

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The sum of three numbers is 113 . The second number is 3 times the third. The first number is 7 less than the third . What are t

OLga [1]

Number 1 = 17
number 2 = 72
number 3 = 24

work:

the three numbers are symbolized as x, y, and z

x + y + z = 113

number 2 (y) is 3 times the third number (z) so

y = 3z

so x + 3z + z = 113

the first number (x) is 7 less than than the third number (z) so

x = z - 7

so z -7 + 3z + z = 113

5z - 7 = 113
5z = 120

z = 24

x = 17
y = 72

Hope this helped :)

8 0

3 years ago