A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
I think it would be 36 it’s what my friend told me I’m not sure though sorry if it’s wrong.
Answer:
Hey there!
8(x-2)+3=-61
8(x-2)=-64
x-2=-8
x=-6
Let me know if this helps :)
Answer: I don’t know
Step-by-step explanation:
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Answer:
139
Step-by-step explanation:
14+14+28+33+33+17 = 139
