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lyudmila [28]
3 years ago
10

George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4

mile every day, which expression shows the number of days in which he went jogging?
9 and 1 over 2 multiplied by 1 over 4


9 and 1 over 2 plus 1 over 4


9 and 1 over 2 divided by 1 over 4


9 and 1 over 2 minus 1 over 4
Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
7 0
HEY BRO IT IS VERY SIMPLE!!

YOUR QUESTION:-
George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging?

MY ANSWER:- 9 and 1 over 2 divided by 1 over 4

we will devide total distance by everyday distance to find this .

HOPE IT HELPS YOU.
antiseptic1488 [7]3 years ago
6 0

Hello,

Question:

George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4 mile every day, which expression shows the number of days in which he went jogging?

We know:

He jogged 9 1/2 miles during October and November

1/4 mile every day

Answer:

9 and 1 over 2 divided by 1 over 4


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The weight of an apple is 150g, rounded to the nearest 5g. what is the lower bound and upper bound?
Aneli [31]

The lower bound is 147.5 and the upper bound is 152.5.

Given the weight of an apple 150 g rounded to the nearest 5g.

We have to find lower bound and upper bound.

Lower bound is an element less than or equal to all the elements in a given set.

Upper bound is an element greater than all the elements in a given set.

Lower bound= Number 1- (Number nearest to  which number 1 is rounded)/2

Upper bound=Number 1+(number nearest to which number 1 is rounded)/2

Weight of an apple =150 g

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Upper bound=150+5/2

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Hence the lower bound is 147.5 and upper bound is 152.5.

Learn more about lower and upper bounds at brainly.com/question/15408313

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4 0
2 years ago
V = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D" id="TexFormula1" title="\frac{4}{3}" alt="\frac{4}{3}" align="absmi
motikmotik

Answer:

The radius of the sphere is 6\ cm

Step-by-step explanation:

we know that

The volume of a sphere is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

V=288\pi\ cm^{3}

substitute and solve for r

288\pi=\frac{4}{3}\pi r^{3}

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Answer:

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here ya go, i hope this is correct if i remember right

Step-by-step explanation:

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