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max2010maxim [7]
3 years ago
6

Express x^-1 y^-2/z^-3 with positive exponents.

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
6 0

\frac{x {}^{ - 1}y {}^{ - 2}  }{z {}^{ - 3} }

if the upper number got power of negative it will go down and the down will go up

So that,

\frac{z {}^{3} }{x {}^{1} {y}^{2}  }

power of 1 can no need to write

pshichka [43]3 years ago
5 0

Negative exponents work like this:

a^{-m} = \dfrac{1}{a^m}

So, a number raised to a negative power simply means the multiplicative inverse of that number raised to the positive power.

So, in your case, you have

\dfrac{x^{-1}y^{-2}}{z^{-3}} = \dfrac{\frac{1}{x}\frac{1}{y^2}}{\frac{1}{z^3}}

We can rework this expression to get

\dfrac{z^3}{xy^2}

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What is the difference in volume between a sphere with radius r and a sphere with radius 0.3r?
REY [17]
The volume of the sphere of radius r is:
 V1 = (4/3) * (pi) * (r ^ 3)
 Where,
 r: sphere radius:
 The volume of the sphere of radius 0.3r is:
 V2 = (4/3) * (pi) * ((0.3r) ^ 3)
 Rewriting:
 V2 = (4/3) * (pi) * (0.027 (r) ^ 3)
 V2 = 0.027 (4/3) * (pi) * (r ^ 3)
 V2 = 0.027V1
 The difference is:
 V1-V2 = V1-0.027V1 = V1 (1-0.027)
 V1-V2 = 0.973 * (4/3) * (pi) * (r ^ 3)
 Answer:
 
the difference in volume between a sphere with radius and a sphere with radius 0.3r is:
 
V1-V2 = 0.973 * (4/3) * (pi) * (r ^ 3)
8 0
3 years ago
Plz, help! I don't know this ! will give brainlest!
Jlenok [28]

Answer:

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7 0
3 years ago
How do you find (2+4i)^3 in rectangular form?
marshall27 [118]

(2+4i)^3=8+48i-96-64i=-88-16i

8 0
3 years ago
Read 2 more answers
Suppose a circle with center (14,9) passes through point (16, 12). Which equation represents the circle?
kifflom [539]

Answer:

( x - 14)^2 + ( y - 9)^2 = 13

Step-by-step explanation:

The equation of the circle with a center and a point

( x - a) ^2 + ( y - b) ^2 = r^2

( 14 , 9) - center-( a, b)

a = 14

b = 9

( 16 , 12) - point - ( x, y)

x = 16

y = 12

Step 1: substitute the center into the equation

( x - 14)^2 + ( y - 9)^2 = r^2

Step 2: substitute the point into the equation

( x - 14)^2 +( y - 9)^2 = r^2

( 16 - 14)^2 + ( 12 - 9)^2 = r^2

2^2 + 3^2 = r^2

4 + 9 = r^2

13 = r^2

Step 3: subs the radius into the equation

( x - 14)^2 + ( y - 9)^2 = r^2

( x - 14)^2 + (y - 9)^2 = 13

Therefore, the equation of the circle is

( x - 14)^2 + ( y - 9)^2 = 13

8 0
3 years ago
Si f(x) es igual a raiz de x al cuadrado menos 16 determinar f(5),f(4),f(6),f(3)
Nadusha1986 [10]

Aplicando la función, los valores numéricos son :

f(5) = -11

f(4) = -12

f(6) = -10

f(3) = -13

La función es dada por:

f(x) = (\sqrt{x})^2 - 16  = x - 16

Para los valores numéricos, reemplazamos x, luego:

f(5) = 5 - 16 = -11

f(4) = 4 - 16 = -12

f(6) = 6 - 16 = -10

f(3) = 3 - 16 = -13

Un problema similar es dado en brainly.com/question/7037337

4 0
3 years ago
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