1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cestrela7 [59]
3 years ago
5

Which lists the ratios in order from greatest to least? 23:24, 11:12, 7:8 23.24, 7:8, 11:12 7:8, 23:24, 11:12 7:8, 11:12, 23:24​

Mathematics
1 answer:
likoan [24]3 years ago
6 0

Answer:I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I. I

Step-by-step explanation:

You might be interested in
g (15 points) Suppose 42 out of 600 rats exposed to a potential carcinogen develop tumors. A control group of 350 rats not expos
vazorg [7]

Answer:

a) The relative risk is 1.8\overline{846153}

b) The attributable risk is 0.69 \overline{047619}

c) There is a relationship between exposure and tumor risk

Step-by-step explanation:

The number of exposed rats that develop tumors, a = 42

The number of rats exposed to the carcinogen = 600 rats

The number of exposed rats that did not develop tumors, b = 600 - 42 = 558

The number of not exposed rats in the control group = 350 rats

The number of rats that develop tumors in the control group, c = 13 tumors

The number of not exposed rats that did not develop tumors, d = 350 - 13 = 337  rats

a) The relative risk, RR = a/(a + b)/(c/(c + d))

∴ RR = (42/(42 + 558))/(13/(13 + 337)) = 49/26 = 1.8\overline{846153}

b) The attributable risk = (a - c)/a

∴ The attributable risk = (42 - 13)/42 = 0.69 \overline{047619}

c) The odds ratio = (a·b)/(c·d)

∴ The odds ratio = 42 × 558/(13 × 337) = 23439/4381 ≈ 5.35

Given that the result of attributable risk is positive, there is an indication that there is a higher probability to develop tumor when exposed to the potential carcinogen, therefore, there is a relationship between exposure and tumor risk

7 0
3 years ago
Copy the incomplete axes and fill in the missing number so that the scaling is consistent.
juin [17]

Answer:

A: write0,4,8,12,16,20 on the line which the answer for A is 16 divided by 4=4

B: Write 0,25,50,75,100,125,150 on the line which the answer for B is 50 divided by 2= 25

5 0
3 years ago
Find the value of x.
Wewaii [24]

Answer:

prob 27

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The ratio of boys to girls in a group is 4:1. If there are 33 more boys than girls, work out how many people there are in total.
MissTica

Total number of people is 55

<u>Step-by-step explanation:</u>

Step 1:

Given ratio between boys and girls is 4:1. Let number of girls be x, so number of boys = 33 + x

⇒ 4x + x = x + 33 + x

⇒ 5x = 33 + 2x

⇒ 3x = 33

⇒ x = 11

Step 2:

Find total number of people.

33 + 2x = 33 + 22 = 55

7 0
3 years ago
Read 2 more answers
A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company prod
tekilochka [14]

Answer:

C) 515 hours.

D) 500 hours

c) sample 3

Step-by-step explanation:

1. Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample Service Life (hours)

1                2              3

495      525            470

500         515           480

505        505            460

<u>500         515             470        </u>

<u>∑2000     2060         1880</u>

x1`= ∑x1/n1= 2000/4= 500 hours

x2`= ∑x2/n2= 2060/4= 515 hours

x3`= ∑x3/n3= 1880/4=  470 hours

2. The mean of the sampling distribution of sample means for whenever service life is in control is 500 hours . It is the given mean in the question and the limits are determined by using  μ ± σ , μ±2 σ  or μ ± 3 σ.

In this question the limits are determined by using  μ ± σ .

3. Upper control limit = UCL = 520 hours

Lower Control Limit= LCL = 480 Hours

Sample 1 mean = x1`= ∑x1/n1= 2000/4= 500 hours

Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample 3 mean = x3`= ∑x3/n3= 1880/4=  470 hours

This means that the sample mean must lie within the range 480-520 hours but sample 3 has a mean of 470 which is out of the given limit.

We see that the sample 3 mean is lower than the LCL. The other  two means are within the given UCL and LCL.

This can be shown by the diagram.

8 0
2 years ago
Other questions:
  • A school earns $70 from selling 50 raffle tickets. Each ticket costs the same price. How much does the school earn for 1 ticket?
    6·2 answers
  • a direct variation function contains the points ( -8, -6 ) and (12,9 ) . Which equation represents the function ?
    14·1 answer
  • A druggist wants to reduce a 20-ounce quantity of a 7% solution of iodine to a 4% solution by adding pure alcohol. How much alco
    9·1 answer
  • Solve completely by using the square root property
    8·1 answer
  • Is the graph increasing, decreasing, or constant?
    12·1 answer
  • Find the least common denominator of these two fractions. LOTO and 1/ 5 The least common denominator is [?]​
    8·1 answer
  • I did the other problems but I dont know these can someone please help me?
    15·2 answers
  • Find the exponential form of 8/27​
    7·1 answer
  • A two-digit integer is randomly selected. What is the probability that its digits are
    6·1 answer
  • How many like terms are in the expression? 14 x minus 14 y + 7 minus x + z + 2 x 0 2 3 5ement best describes Japan’s economy und
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!