In a certain city, the hourly wage of workers on temporary employment contracts is normally distributed. The mean is $15 and the
standard deviation is $3. What percentage of temporary workers earn less than $12 per hour? A. 6% B. 16% C. 26% D. 36%
2 answers:
Answer:
B. 16%
Step-by-step explanation:
In the picture attached, the standard normal distribution table is shown.
The value of Z is computed as follows:
Z = (x - μ)/σ
where x is the value of interest ( = 12), μ is the mean ( = 15) and σ is the standard deviation (= 3). Replacing:
Z = (12 - 15)/3 = -1
From the table, the probability is 0.1587, approximately equal to 16%
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