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shepuryov [24]
3 years ago
12

Please help me with this. What is the slope of a line parallel to the line with equation 5x-2y=11?

Mathematics
2 answers:
Vlad [161]3 years ago
7 0
Use the slope-intercept form y = mx + b to find the slope, m.

5x - 2y = 11  this equation is given in standard form 

-2y = 11 + 5x    add both sides by 5x and then divide all by -2

y = 5/2x - 11/2  

so the slope is 5/2.

hope this helped, God bless!
kari74 [83]3 years ago
6 0
The slope of a line parallel to another line must have the same slope as the other line. So therefore, we just want to first find the slope of this line.

To do this, we can switch it to slope intercept form, which is y = mx + b.

-2y = -5x + 11

Notice that the y doesn't have a variable next to it in slope intercept form. This means you have to divide all the sides to -2 to cancel out that -2.

-2y = -5x + 11
/-2     /-2     /-2

y = 5/2x + 11/-2

Since in the equation, y = mx + b, the number in the position of m = the slope, we know that 5/2 is the slope.

So therefore, the slope of a line parallel to the line with equation 5x - 2y = 11 must be 5/2.
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?

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We know that Angle Bisector Divides an Angle into Two Equal Angles.

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