What is the sum of 4m(m-6) and 8(m-4)?
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The speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.
A star moving away from the observer (say on Earth) will have its emitted light red-shifted (move to lower frequency), i.e., the spectrum moving to left if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.
A star moving towards the observer (say on Earth) will have its emitted light blue-shifted (move to higher frequency), i.e., the spectrum moving to the right if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.
A star moving perpendicular to the observer (say on Earth) will have its emitted light will no change with respect to the spectrum of the stationary star.
These are due to the Doppler effect, the equation of frequency detected by the observer as
where
, v the relative velocity of the moving source (the star here), f^s is the frequency of light emitted by the source.
Hence the answer is the speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.
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