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3 years ago

What is the sum of 4m(m-6) and 8(m-4)?

Mathematics

1 answer:

Alik [6]3 years ago

7 0

Step-by-step explanation:

4m2 - 24m + 8m - 32

4m2 - 16m - 32

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The length of a rectangle is 4 inches more than its width, and its perimeter is 34 inches. Find the length and width of the rect

VashaNatasha [74]

The length would be w+4 since it is 4 inches more than the width, which is w.

4 0

3 years ago

Read 2 more answers

Walter has 3 more red peppers than green peppers. In all, he has 35 peppers. How many green peppers does Walter have?

Oksanka [162]

Answer:

Step-by-step explanation:

16+19=35

19-16=3

16 green peppers

8 0

3 years ago

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

3 years ago

Reposting this because no body gave me the equation. An equation would be appreciated :)

o-na [289]

bring the like terms together,

$\frac{6q}{5} + \frac{4q}{5} \leqslant 28 + 3 + 3 - 3$

$\frac{10q}{5} \leqslant 31$

$2q \leqslant 31$

$q \leqslant \frac{31}{2}$

3 0

3 years ago

Read 2 more answers

The public library has to move 42,000 books to its new location. The movers can pack an average of 45 books in every box. The tr

Anni [7]

Answer:

<h2> 934boxes</h2><h2> 4 trips</h2>

Step-by-step explanation:

Given the total number of books 42,000

Ok, firstly let us calculate the number of boxes required, given that a box can contain 45 books

number of boxes= 42,000/45

number of boxes=933.3 boxes

approximately 934boxes

Also, given that the truck can carry online 250 boxes in one trip

then it must make 934/250= 3.7 trips

approximately the truck will make 4 trips to carry all the boxes

7 0

4 years ago