The question is incomplete, complete question is :
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution? The pka of acetic acid is 4.74.
Answer:
33.11 millimoles of acetate we will need to add to this solution.
Explanation:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
![pH=pK_a+\log(\frac{[salt]}{[acid]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%29)
Where :
tex]pK_a[/tex] = negative logarithm of acid dissociation constant of acid
[salt] = Concentration of salt
[Acid] = Concentration of salt
We have:
pH = 5.26
[salt] =![[CH_3COO^-]](https://tex.z-dn.net/?f=%5BCH_3COO%5E-%5D)
= ?
[acid] = ![[CH_3COOH]=10.0 mmol](https://tex.z-dn.net/?f=%5BCH_3COOH%5D%3D10.0%20mmol)
![5.26=4.74+\log(\frac{[CH_3COO^-]}{[10.0 mmol]})](https://tex.z-dn.net/?f=5.26%3D4.74%2B%5Clog%28%5Cfrac%7B%5BCH_3COO%5E-%5D%7D%7B%5B10.0%20mmol%5D%7D%29)
![[CH_3COO^-]=33.11 mmol](https://tex.z-dn.net/?f=%5BCH_3COO%5E-%5D%3D33.11%20mmol)
33.11 millimoles of acetate we will need to add to this solution.
We know that,
acceleration (a) = final velocity(V)-initial velocity(U)/ Time taken(T)
Hello!
BeH₂ is a linear molecule, while CaH₂ is an angular molecule.
The difference between these two molecules is given by the number of electrons they have. Be is in the 2nd period of the Periodic table, and the ion Be⁺² doesn't have any free electron pairs when bonding to H. Ca is in the 4 period of the periodic table, meaning that it has more electrons, and the ion Ca⁺² has two free electron pairs when bonding to H that makes the molecule angular by pushing the bonds at an angle by sterical hindrance.
Have a nice day!
a. atoms
Explanation:
Let's take as example carbon and lead. Carbon have an atomic mass of 12 a.m.u while lead have an atomic mass of 207 a.m.u. Value of atomic masses are the same with as the value of molar masses. So carbon have a molar mass of 12 g/mole while lead have a molar mass of 207 g/mol.
Avogadro's number it tell us that in 1 mole of particular substance there are 6.022 × 10²³ particles. Taking in account this, in 12 g of carbon there are 6.022 × 10²³ carbon atoms and in 207 g of lead there are 6.022 × 10²³ lead atoms atoms.
The atomic mass of any two elements contain the same number of atoms.
Learn more about:
Avogadro's number
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