Answer:
Explanation:
To interpret this pedigree, let’s start with information that we already know:
Brown is recessive, which means brown individuals must have the phenotype BB. In this pedigree, brown individuals are filled in.
Black is dominant, which means black individuals must have at least one B allele. Their phenotype could be either BB or BB. In this pedigree, black individuals are not filled in.
Figure 5 shows the same pedigree, but with information about the individual’s phenotype filled in.
The shaded individual, who is a brown female puppy, must have the phenotype BB. If she had any B alleles, she would be black because the black allele is dominant over the brown allele.
In order for the brown puppy to have the phenotype BB, she must have gotten two “b” alleles: one from each of her parents. We know that her parents are both black (because they are unshaped), which means they must have a least one “B” allele. This means that both parents must be heterogeneous: BB.
The three black puppies must have at least one “B” allele in order for them to be black in color. However, we can’t tell whether they are homologous dominant (BB) or heterogeneous (BB) since both of those phenotype would result in black color. One way to represent this on a pedigree is B-, meaning that the second allele could be either B or b.
Answer:
I believe they deserve to be here.
Explanation:
A chemist (from Greek chēm (ía) alchemy; replacing chemist from Medieval Latin alchimista[1]) is a scientist trained in the study of chemistry. Chemists study the composition of matter and its properties. Chemists carefully describe the properties they study in terms of quantities, with detail on the level of molecules and their component atoms. Chemists carefully measure substance proportions, reaction rates, and other chemical properties. The word 'chemist' is also used to address Pharmacists in Commonwealth English.
There is not enough information for me to answer this question.
Answer:
Molarity of sucrose = 0.116 M (Approx.)
Explanation:
Given:
Volume of solution = 0.5 liter
Mass of sucrose in gram = 20 gram
Molar mass of sucrose 342.3 g/mol
Find:
Molarity of sucrose
Computation:
Mole of sucrose = Mass of sucrose in gram / Molar mass of sucrose
Mole of sucrose = 20 / 342.3
Mole of sucrose = 0.058 (Approx.)
Molarity of sucrose = Mole of sucrose / Volume of solution
Molarity of sucrose = 0.058 / 0.5
Molarity of sucrose = 0.116 M (Approx.)