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GREYUIT [131]
3 years ago
8

What is the energy produced through cellular respiration called?

Chemistry
1 answer:
tresset_1 [31]3 years ago
4 0

Answer:

During the process of glycolysis in cellular respiration, glucose is oxidized to carbon dioxide and water. Energy released during the reaction is captured by the energy-carrying molecule ATP (adenosine triphosphate).

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In part 3 of the lab, you discovered the relationship between temperature (T) and volume (V) of a gas.
rewona [7]

\frac{V1}{T1} = k

<u>Explanation:</u>

The relation between volume, V of gas and Temperature, T of a gas is related by Charles Law.

This law states that the volume of a given amount of gas held at a constant pressure is directly proportional to the Kelvin temperature

Thus,

\frac{V}{T} = k

where k is a constant

Therefore,

\frac{V1}{T1} = \frac{V2}{T2\\} = \frac{V3}{T3} ...

This shows, as the volume of a gas goes up, the temperature also goes up and vice-versa.

7 0
3 years ago
4.5 moles of sodium sulfate contain how many atoms of sulfur
Hatshy [7]
Chemical Formula of Sodium Sulfate is Na₂SO₄.

As we know, 1 mole of any substance contains 6.022 × 10²³ particles. So, 1 mole of Na₂SO₄ also contains 6.022 × 10²³ formula units of Na₂SO₄.
Also,
                     1 mole of Na₂SO₄ contains  =  6.022 × 10²³ Atoms of S
So,
            4.5 moles of Na₂SO₄ will contain  =  X atoms of S

Solving for X,
                                X  =  (4.5 moles × 6.022 × 10²³ Atoms) ÷ 1 mole

                                X  =  2.70 × 10²⁴ Atoms of S
Result:
            4.5 Moles 
of Na₂SO₄ contains 2.70 × 10²⁴ Atoms of Sulfur.
3 0
3 years ago
An ion of an element can have the same ________ as another element.
Vera_Pavlovna [14]

Answer:

Number of electrons.

Explanation:

I hope this helps.

6 0
4 years ago
How can I get the percentage recovery?
frosja888 [35]
If you collected 7.0 grams of something the percentage recovery would be 70% (7/10 x 100).
^
^
^
A percentage recovery is something like that
3 0
3 years ago
A silver nitrate, AgNO3, solution of unknown concentration was discovered in the lab. To determine the concentration of the solu
harina [27]

Answer:

0.174 M

Explanation:

The same can be solve by using Nernst's equation

The Nernst's equation is:

Ecell=E^{0}_{cell}-\frac{0.0592}{n}log\frac{[anodic]}{[cathodic]}

For silver cell

n= 1

As both the compartments have silver nitrate solution,t the standard emf of cell will be zero.

Given

Ecell = 0.045

[Anodic compartment]= 1 M

Putting values

0.045 = 0 -\frac{0.0592}{1}log(\frac{1}{x} )

0.760=log(\frac{1}{x})

Taking antilog and solving

[AgNO3]=0.174 M

3 0
4 years ago
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