Question

When dinitrogen pentaoxide, a white solid, is heated, it decomposes to produce nitrogen dioxide gas and

Answer 1

9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

Oxygen produced - 1.618 gram

Decomposition of $N_2O_5$ takes place.

Find - Amount of $NO_2$ produced.

The decomposition reaction is as follows -

$2N_2O_5$--> $4NO_2 + O_2$

Moles of $O_2$ gas =$\frac{1.6}{16}$  =0.1 moles.

1 mole of $O_2$ is produced from 2 moles of dinitrogen pentoxide

0.1 mole of $O_2$  will be produced from = 0.2 moles.

Now, 2 moles of dinitrogen pentoxide produce 4 moles of $NO_2$

$NO_2$ produced will be - 0.4 moles.

Weight of $NO_2$ produced - 0.4 X 46

Weight of $NO_2$  produced - 18.4 gram

Thus, grams of $NO_2$ produced are 18.4

Now calculate the volume of $NO_2$

Given data are:

P=103.25 kPa =1.01899827 atm

T= 22.75 °C +273 = 295.75 K

n=0.4 moles

V=?

R= 0.0821 liter·atm/mol·K

Putting the value in PV=nRT

V =  $\frac{nRT}{P}$

V =  $\frac{0.4 \;moles \;X \;0.0821\; liter\;atm/\;mol \;K X \;295.75 \;K}{1.01899827 atm}$

V= 9.5314 L

Hence, 9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

Learn more about the ideal gas equation here:

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