Answer:
quantity a is halfed
Corrected question;
A quantity a varies inversely as a quantity b, if, when b changes a changes in the inverse ratio. What happens to the quantity a if the quantity b doubles?
Step-by-step explanation:
Analysing the question;
A quantity a varies inversely as a quantity b,
a ∝ 1/b
a = k/b ......1
when b changes a changes in the inverse ratio;
Since the change at the same ratio but inversely, k = 1
So, equation 1 becomes;
a = 1/b
If the quantity b doubles,
ab = 1
a1b1 = a2b2
When b doubles, b2 = 2b1
a1b1 = a2(2b1)
Making a2 the subject of formula;
a2 = a1b1/(2b1)
a2 = a1/2
Therefore, when b doubles, a will be divided by 2, that means a is halfed.
The third one.
Because the answer of the absulate value equations is always positive.
Answer:
158 degrees is angle b I think so
When you write a function in the form
, y is the dependent variable, and x is the independent variable.
So, if b is the independent variable, it means that we have to solve the expression for r.
To do so, we perform the following steps: start with

Add 12 to both sides

Divide both sides by 4:

So, we wrote the expression in the form
, which means that r is the dependent variable and b is the independent variable, as requested.